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3 years ago

The independent variable of a data set is r, while the dependent variable is s. which of these is an explanatory variable?

Mathematics

1 answer:

irina [24]3 years ago

3 0

Explanatory variable = independent variable = r

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PLEASE HELP!!!

olga55 [171]

The value of y has changed at a much greater rate. If the x-axis represents time and the y-axis distance, as is the case in many applications, then the rate of change of y with respect to x -- of distance with respect to time -- is called speed or velocity.

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3 years ago

11°F, 58°F, 20°F, -2°F, 2°F, and -5°F. Write the temperatures in order from hottest to coldest.

bazaltina [42]

Answer:

58°F, 20°F,11°F, 2°F , -2°F, -5°F

5 0

3 years ago

Read 2 more answers

12) Add the fractions, and simplify if possible. (y+7)/(y^2-y-12) - 2/(y^2-9)

lianna [129]

Answer:

$\dfrac{y^2+2y-13}{(y-4)(y+3)(y-3)}$

Step-by-step explanation:

Given the expression

$\dfrac{y+7}{y^2-y-12}-\dfrac{2}{y^2-9}$

First, factor each denominator:

1. $y^2-y-12=y^2-4y+3y-12=y(y-4)+3(y-4)=(y-4)(y+3)$

2. $y^2-9=(y-3)(y+3)$

Now the expression is

$\dfrac{y+7}{(y-4)(y+3)}-\dfrac{2}{(y-3)(y+3)}$

Now, multiply the first numerator by (y-3) and the second by (y-4) and write the result as a fraction with denominator $(y-4)(y+3)(y-3):$

$\dfrac{(y+7)(y-3)-2(y-4)}{(y-4)(y+3)(y-3)}=\dfrac{y^2-3y+7y-21-2y+8}{(y-4)(y+3)(y-3)}=\dfrac{y^2+2y-13}{(y-4)(y+3)(y-3)}$

This fraction cannot be simplified more.

3 0

4 years ago

Solve the inequality 3/7(35x-14)less then or equal to 21x/2+3

Bingel [31]

15x-6 $\leq$ 21x/2+3. Multiply everything by 2: 30x-12=21x+6. Combine like terms: 9x=18. Get the unknown by itself: 9x/9=X. 18/9=2. X is less than or equal to 2 :)

5 0

4 years ago

Sergeeva-Olga [200]

Answer: 114.37 ft

Step-by-step explanation:

If we model this situation as a right triangle, where the hypotenuse is the length of the ladder ( $110 ft$ ), the opposite leg is the height the ladder will reach $h$ , and the adjacent leg is the distance between the base of the ladder and the building ( $28 ft$ ); we have two options:

1) Using trigonometric functions, since we are given the angle $\theta=75\°$

2) Using the Pithagorean Theorem

Any of the options will give a similiar result. So, let's choose the Pithagorean Theorem:

$(hypotenuse)^{2}=(opposite-leg)^{2}+(adjacent-leg)^{2}$

$(110 ft)^{2}=(h)^{2}+(28 ft)^{2}$

Isolating $h$ :

$h=\sqrt{(110 ft)^{2}-(28 ft)^{2}}$

$h=106.37 ft$

Adding to this height the extra height of $8 ft$ (since the base of the ladder is at this distance above the ground, perhaps held by a firefighter truck):

$h=106.37 ft+8 ft=114.37 ft$ This is the height the ladder will reach

6 0

3 years ago