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Gelneren [198K]
3 years ago
14

Please help to solve this problemfactorize:(1 - a^2) (1 - b^2) + 4ab​

Mathematics
1 answer:
Temka [501]3 years ago
4 0

Answer:

(ab+a-b+1)(ab-a+b+1)

Step-by-step explanation:

  • (1 - a²) (1 - b²) + 4ab​=
  • 1 -a²-b² +a²b² +4ab =
  • (a²b² +2ab +1 )- (a²-2ab+b²)=
  • (ab+1)² - (a-b)²=
  • (ab+1 +a-b)(ab+1 -a+b)=
  • (ab+a-b+1)(ab-a+b+1)

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Evaluate the quantity 3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two.
chubhunter [2.5K]

The value of the expression given as  [3² * 3⁻⁵]/[5⁻²] is 25/27

<h3>How to evaluate the expression?</h3>

The expression is given as:

3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two

Rewrite properly as:

[3² * 3⁻⁵]/[5⁻²]

Apply the negative exponent law of indices

So, we have

[3² * 3⁻⁵]/[5⁻²] = [5²]/[3⁻² * 3⁵]

Apply the exponent law of indices

[3² * 3⁻⁵]/[5⁻²] = [5²]/[3³]

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