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3 years ago

Please help to solve this problemfactorize:(1 - a^2) (1 - b^2) + 4ab

Mathematics

1 answer:

Temka [501]3 years ago

4 0

Answer:

(ab+a-b+1)(ab-a+b+1)

Step-by-step explanation:

(1 - a²) (1 - b²) + 4ab=
1 -a²-b² +a²b² +4ab =
(a²b² +2ab +1 )- (a²-2ab+b²)=
(ab+1)² - (a-b)²=
(ab+1 +a-b)(ab+1 -a+b)=
(ab+a-b+1)(ab-a+b+1)

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Help me please thank you

oee [108]

Hello from MrBillDoesMath!

Answer:

2(x+8) = 40

Discussion:

Rewrite the original Question as

" Twice the (sum of a number and 8) is 40" =>

2 ( x + 8 ) = 40 =>

2 (x+8) = 40

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Thank you,

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7 0

3 years ago

13.48x - 200 < 256.12

podryga [215]

Answer:

x < 33.84

Step-by-step explanation:

we have

13.48x-200 < 256.12

Solve for x

Adds 200 both sides

13.48x-200 +200 < 256.12+200

13.48x < 456.12

Divide by 13.48 both sides

13.48x/13.48 < 456.12/13.48

x < 33.84

The solution is the interval ----> (-∞, 33.84)

All real numbers less than 33.84

5 0

3 years ago

Partial products and regrouping diferences

Maslowich

What's your question?

8 0

3 years ago

Which expression is equivalent to (x Superscript one-half Baseline y Superscript negative one-fourth Baseline z) Superscript neg

Darina [25.2K]

By using exponent properties, we will get the simplified expression:

$x^{-1}*y^{1/2}*z^2$

<h3>How to simplify the given expression?</h3>

Here we have the expression:

$(x^{1/2}*y^{-1/4}*z)^{-2}$

Remember the exponent properties:

$(a^n)^m = a^{n*m}$

And:

$(a*b)^n = (a^n)*(b^n)$

So using these two properties, we can rewrite:

$(x^{1/2})^{-2}*(y^{-1/4})^{-2}*(z)^{-2}\\\\(x^{-2*1/2})*(y^{-2*-1/4})*(z^{-2}})\\\\x^{-1}*y^{1/2}*z^2$

So we conclude that the completely simplified expression is:

$x^{-1}*y^{1/2}*z^2$

If you want to learn more about exponents:

brainly.com/question/8952483

#SPJ1

8 0

2 years ago

Find the area of a parallelogram with the given vertices. P(-2, -5), Q(9, -5), R(1, 5), S(12, 5)

valentina_108 [34]

Answer:

The area of the parallelogram is 55 square unit.

Step-by-step explanation:

The area of a parallelogram is

$A=\frac{1}{2}\times base\times height$

It is given that the vertices of the parallelogram are P(-2, -5), Q(9, -5), R(1, 5), S(12, 5).

Plot these points on a coordinate plane, and draw a perpendicular on PQ from the point R.

From the graph is clear that length of PQ is 11 and the height of the parallelogram is 10. So, the area of a parallelogram is

$A=\frac{1}{2}\times 11\times 10$

$A=55$

Therefore the area of the parallelogram is 55 square unit.

4 0

2 years ago

Please help to solve this problemfactorize:(1 - a^2) (1 - b^2) + 4ab​

Please help to solve this problemfactorize:(1 - a^2) (1 - b^2) + 4ab