Answer:
42 = <em>l</em>
21 = <em>w</em>
Step-by-step explanation:
{l = 2<em>w</em>
{126 = 2<em>w</em> + 2<em>l</em>
126 = 2<em>w</em> + 2[2<em>w</em>]
126 = 2<em>w</em> + 4<em>w</em>
126 = 6<em>w</em>
21 = w [Plug this back into both equations to get the length of 42]; 42 = <em>l</em>
I am joyous to assist you anytime.
Answer:
In an isosceles triangle, the legs of the triangle have same lengths.
• substitute:
Answer:
the equation of the hyperbola is;(x²/81) - (y²/1600) = 1
Step-by-step explanation:
We are given that the hyperbola has;
Centre; 0,0
Vertex; 9,0
Focus; 41,0
Thus,the vertex and focus are on the x-axis. Thus, the equation for the hyperbola will have the form;
(x²/a²) - (y²/b²) = 1
Since The vertex is (9,0),so
a = 9 and a² = 9² = 81
Also,Since The focus is (41,0),so
c = 41 and c² = 41² = 1681
Solving for b², we have;
b² = c² - a²
b² = 1681 - 81
b² = 1600
b = √1600
b = 40
Thus,equation of hyperbola is;
(x²/9²) - (y²/40²) = 1
Which gives;
(x²/81) - (y²/1600) = 1
(5-0)^2+(3-3)^2
25+0
The square root of 25 is 5
The distance is 5.
Answer:
30
Step-by-step explanation:
You can use the triangle area theorem-
15x4(/2)=30
