T(3)=3(3)-1
T(3)=9-1
T(3)=8
answer is 8
Answer:
Hello! answer: area is 6 cm2
Step-by-step explanation:
Triangle area formula: base × height ÷ 2 or base × height × 1/2 so...
12 × 16 = 192 192 ÷ 2 = 96
12 ÷ 4 = 3
16 ÷ 4 = 4
3 × 4 = 12 12 ÷ 2 = 6 therefore the area is 6 hope that helps!
Answer:
Lowest angle of the triangle with hypotenuse of 2.9ft and a leg of 2.6ft is 26.29°.
Explanation:
A triangle has a hypotenuse of 2.9ft and a leg of 2.6ft
We have smallest angle = Angle C
We have, Cos C = AC/BC
= 2.6/2.9
= 0.897
C = 26.29°
So lowest angle of the triangle with hypotenuse of 2.9ft and a leg of 2.6ft is 26.29°.
One pound of the item will cost 4.74 bill
Step-by-step explanation:
In this problem, we are told that Delia bought 4.5 pounds of fruit
and paid with a toa total bill of 20+5= 25 bill
and also she received a change of 3.67
this means that the item she bought cost 25-3.67= 21.33bill
now if 4.5 pounds of items cost 21.33 bill
then 1 pound will cost Xbill
cross multiply and solve for Xbill
X= 21.33/4.5
X= 4.74 bill
One pound of the item will cost 4.74 bill
1) First try to find a perfect square number that divides evenly into the number under the square root. Perfect square numbers include 4, 9, 16, 25, 36, 49, etc. because they are squares of the numbers 2, 3, 4, 5, 6, 7, etc., respectively.
2) Separate the root expression into the two numbers you found as factors, with each number now under its own square root symbol. For example, sqrt(12) = sqrt(4) times sqrt(3).
3) Keep simplifying. The square root of a perfect square becomes just a number, without the radical square root symbol. sqrt(4)*sqrt(3) becomes 2*sqrt(3).
4) Check to see if anymore simplifying can be done, either by combining constants or finding another perfect square number that divides evenly into your factors. If no more simplifying can be done, you have your final "simplified radical form" (SRF) answer, 2*sqrt(3).
If there is a square root anywhere in the DENOMINATOR, you must "rationalize" the denominator, in other words, somehow get rid of the root in the bottom, in order for the expression to be considered simplest. For example, if you have 4/sqrt(2) you must use the trick of simplifying by multiplying the expression by sqrt(2)/sqrt(2). This will clear the square root in the bottom. If you multiply straight across, you would get 4*sqrt(2)/2, which simplifies again to 2*sqrt(2).
<span>If you have a more complicated fraction with a square root in the denominator, like (4+sqrt(3))/(5-sqrt(3)), you will need to use the "conjugate" to simplify. This means multiplying top and bottom by the expression in the denominator, but with the middle sign flipped. Here you would multiply by (5+sqrt(3))/(5+sqrt(3)), multiply straight across on top and bottom using FOIL-ing and distribution. Some terms will cancel in the bottom, leaving you with a simpler denominator that has no square roots.</span>
