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MrRissso [65]
3 years ago
11

What is the solution to the equation One-third (x minus 2) = one-fifth (x + 4) + 2? x = 12 x = 14 x = 16 x = 26

Mathematics
1 answer:
Elena L [17]3 years ago
3 0

Answer:

x = 26

Step-by-step explanation:

Given

\frac{1}{3} (x - 2) = \frac{1}{5} (x + 4) + 2

Multiply through by 15 to clear the fractions

5(x - 2) =3(x + 4) + 30 ← distribute and simplify both sides

5x - 10 = 3x + 12 + 30, that is

5x - 10 = 3x + 42 ( subtract 3x from both sides )

2x - 10 = 42 ( add 10 to both sides )

2x = 52 ( divide both sides by 2 )

x = 26

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What are the coordinates of the endpoints of the segment
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Rewrite the radical expression as an expression with a rational exponent. the seventh root of x to the third power
kherson [118]

The expression with a rational exponent of the seventh root of x to the third power is x to the three sevenths power ⇒ answer A

Step-by-step explanation:

Let us explain how to change the radical expression as an expression

with a rational exponent

1. Find the number of the root and make it the denominator of the

  fraction exponent

2. Find the power of the term under the radical and make it the

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Examples:

\sqrt{x^{n}}=x^{\frac{n}{2}}

\sqrt[3]{x^{n}}=x^{\frac{n}{3}}

\sqrt[5]{x^{n}}=x^{\frac{n}{5}}

So \sqrt[m]{x^{n}}=x^{\frac{n}{m}}

∵ the radical expression is the seventh root of x to the third power

∵ seventh root = \sqrt[7]{}

∵ x to the third power = x³

∴ seventh root of x to the third power = \sqrt[7]{x^{3}}

Let us change it to the rational exponent

∵ \sqrt[m]{x^{n}}=x^{\frac{n}{m}}

∵ \sqrt[7]{x^{3}}

∴ m = 7 and n = 3

∴ \sqrt[7]{x^{3}} = x^{\frac{3}{7}}

∵ x^{\frac{3}{7}} is x to the three sevenths power

∴ \sqrt[7]{x^{3}} is x to the three sevenths power

The expression with a rational exponent of the seventh root of x to the third power is x to the three sevenths power

Learn more:

You can learn more about radical equation is brainly.com/question/7153188

#LearnwithBrainly

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