Z-scores are expressed in terms of standard deviations from their means. <span>The standard score is simply the score, minus the mean score, divided by the standard deviation. It is calculated as follows:

z = X- mean / standard deviation
z = 2.7 - 2.4 / 1.5
z = 0.2</span>

5 0

3 years ago

Maria throws a softball straight up into the air with an initial velocity of 50 ft/sec. The ball leaves her hand when it is exac

Nataly_w [17]

Answer:

The equation that models the situation is $s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}$ .

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

$v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o})$ (1)

Where:

$s_{o}$ , $s_{f}$ - Initial and final position of the softball, measured in feet.

$a$ - Acceleration, measured in meters per square second.

$v_{o}$ , $v_{f}$ - Initial and final velocities of the softball, measured in feet per second.

If we know that $v_{o} = 50\,\frac{ft}{s}$ , $a = -32.174\,\frac{m}{s^{2}}$ and $s_{o} = 4\,ft$ , then the equation that models the situation is:

$v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)$

Then, we clear the final position of the softball:

$-\frac{v_{f}^{2}-2500}{-64.348} = s_{f}-4$

$s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}$

The equation that models the situation is $s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}$ .

8 0

2 years ago

A process is controlled with a fraction nonconforming control chart with three-sigma limits, n = 100, UCL = 0.161, center line =

photoshop1234 [79]

Answer:

Lets Recall, p= 0.080, n=100, UCL= 0.161

Then np=100, 0.080=8

Step-by-step explanation:

The full steps or solution to this is in an an attached document.

4 0

3 years ago

Scores are 78,81,83, and 76 what must she earn on the fifth test to earn an average test score of 81

iogann1982 [59]

The average value of a data set is equal to the sum of each entry divided by the number of entries. In this case, we have 5 scores, so we can find set up the following equation where x is the fifth score:

$\dfrac{78+81+83+76+x}{5} = 81$

Now solve for x:

$78 + 81 + 83 + 76 + x = 81(5)$

$318 + x = 405$

$x = 87$

The fifth score must be 87.

6 0

2 years ago

Read 2 more answers