I could be wrong but I got 28. I devided 420 by 15
Answer:
The 9 ounce box is the better deal, and Kyle will save 2 cents.
Step-by-step explanation:
First, you should find how much 1 once would cost in the 9 ounce box.
Do 2.52 ÷ 9 = x
x = 0.28
This means that in the <u>9 ounce box, one ounce costs 28 cents</u>.
Now, find how much one once would cost in the 12 ounce box.
3.60 ÷ 12 = x
x = 0.30
This means that in the <u>12 ounce box, one ounce costs 30 cents</u>.
This means that the 9 ounce box is a better deal, because it costs less per ounce.
0.30 - 0.28 = 0.02. This means there is a 2 cent difference in their prices per ounce.
So, Kyle should choose the 9 ounce box, and he will save 2 cents per box.
Step-by-step explanation:
Okay! To do this you need to have x on one side (isolate the variable) and also combine like terms. Like terms are terms with the same exponent and variable, like 8x and 6x.
8x+1=-6x-2 To combine like terms here we have to move -6x to the other side of the equation by adding it (using inverse operations). 8x+6x=14x
14x+1=-2 now subtract 1 from both sides.
14x=-3
Divide both sides by 14 and x=-3/14
Brainliest? :)
Answer:
18.67% probability that the sample proportion does not exceed 0.1
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
For the sampling distribution of a sample proportion, we have that 
In this problem, we have that:
What is the probability that the sample proportion does not exceed 0.1
This is the pvalue of Z when X = 0.1. So
has a pvalue of 0.1867
18.67% probability that the sample proportion does not exceed 0.1
Yes I think so if not am sorry
