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3 years ago

Find the value please

Mathematics

1 answer:

DanielleElmas [232]3 years ago

7 0

The answer is 48. I'm sorry I can't explain cuz it's a long process

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Can some one explain to me what substitution is and how to use it to solve equations?

Yakvenalex [24]

Answer:

Step-by-step explanation:

Say that your equation is 2x+4=8, x=2

you would plug in the 2 where your x is so, 2(2) +4=8

then you'd solve regularly.

Hope my answer has helped you!

5 0

4 years ago

Triangle ABC is congruent to triangle DEF. If DE = 41, EF = 23, DF = 36, and AB = 8x − 7, what is x? Round to the nearest tenth.

Nadya [2.5K]

The side AB is equal to the side DE. Then the value of x is 6.

<h3>What is the triangle?</h3>

A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.

Triangle ABC is congruent to triangle DEF.

If DE = 41, EF = 23, DF = 36, and AB = 8x − 7.

Then the side AB is equal to the side DE.

AB = DE

8x - 7 = 41

8x = 48

x = 6

Then the value of x is 6.

More about the triangle link is given below.

brainly.com/question/25813512

#SPJ1

5 0

2 years ago

Read 2 more answers

You roll a 6 sided dice what is the probability of rolling a number greater than two and then rolling a number less than three

Alexandra [31]

First answer is 4 chances and second answer is 2 chances

5 0

4 years ago

Paula is training take part in a fun run fir charity. Paula weighed 65.5 kilogram before she started her training. She has list

lesantik [10]

We can convert grams to kilograms by dividing by 1000.
3500÷1000=3.5kg

Now we subtract this from her original weight
65.5-3.5= 62kg

8 0

3 years ago

Determine determine whether the following geometric series converges or diverges. if the series converges find its sum.

Lilit [14]

For starters,

$\dfrac{3^k}{4^{k+2}}=\dfrac{3^k}{4^24^k}=\dfrac1{16}\left(\dfrac34\right)^k$

Consider the $n$ th partial sum, denoted by $S_n$ :

$S_n=\dfrac1{16}\left(\dfrac34\right)+\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\cdots+\dfrac1{16}\left(\dfrac34\right)^n$

Multiply both sides by $\frac34$ :

$\dfrac34S_n=\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\dfrac1{16}\left(\dfrac34\right)^4+\cdots+\dfrac1{16}\left(\dfrac34\right)^{n+1}$