Factorization of sin²θ + sin²θ cos²θ gives us; 2sin²θ - sin⁴θ
<h3>How to simplify Trigonometric Functions?</h3>
We want to simplify;
sin²θ + sin²θ cos²θ
Let us factorize out sin²θ to get;
sin²θ(1 + cos²θ)
Now, we know that cos²θ = 1 - sin²θ
Thus;
sin²θ(1 + cos²θ) = sin²θ(1 + 1 - sin²θ)
⇒ sin²θ(2 - sin²θ)
⇒ 2sin²θ - sin⁴θ
Read more about Trigonometric functions at; brainly.com/question/6904750
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Step-by-step explanation: Latitude: 48.30781, Longitude: -127.14321, Distortion: 2.26
Answer:
Step-by-step explanation:
In Δ ABC & ΔADC
AC bisect ∠BCD given
∠ACB ≅ ∠ACB AC bisect ∠BCD
DC ⊥ AD Given
BC ⊥ AB Given
∠ABC = ∠ADC Right angles are ≅
AC ≅ AC Common to both triangle ΔABC & ΔADC
ΔABC ≅ ΔADC AAS congruent
BC ≅ DC CPCT
It’s D because 10/3 is 3.3333, 3.3, the little thing (I forgot what it’s called) is always 3.14, and 11/4 is 2.75