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3 years ago

How many solutions does this linear system have?

Mathematics

1 answer:

Andrews [41]3 years ago

8 0

Answer:

x = 0 , y = 4

Step-by-step explanation:

Solve the following system:

{y = 4 - 3 x | (equation 1)

x + 2 y = 8 | (equation 2)

Express the system in standard form:

{3 x + y = 4 | (equation 1)

x + 2 y = 8 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{3 x + y = 4 | (equation 1)

0 x+(5 y)/3 = 20/3 | (equation 2)

Multiply equation 2 by 3/5:

{3 x + y = 4 | (equation 1)

0 x+y = 4 | (equation 2)

Subtract equation 2 from equation 1:

{3 x+0 y = 0 | (equation 1)

0 x+y = 4 | (equation 2)

Divide equation 1 by 3:

{x+0 y = 0 | (equation 1)

0 x+y = 4 | (equation 2)

Collect results:

Answer: {x = 0 , y = 4

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I'll do (a) and (b) as examples. Make sure your calculator is set to degrees, not radians.

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