That’d be A and B(1st and 2nd). :)
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If I assume that random segregation of chromosomes takes place during spermatogenesis and all sperms are viable then I will take the male through meiosis.
The three chromosomes are +, +, ey
Then you double them into sister chromatids which is ++, ++, eyes.
If I consider all possible alignments during metaphase as, the three homologous pairs and gather at the metaphase plate.
Remember that any two of the three pairs will join together and odd pair out will line up at the metaphase plate with no partner pair.
There are three different arrangements which are possible for the three homologous pairs.
Two of the three possible arrangements will segregate and make two sperm with +ey and two sperm with +. The other arrangement will segregate and make two sperm with ++ and two sperm with ey.
When meiosis is being done, then the sperm genotypes and their proportions are,
1/3+ey, 1/3+, 1/6++, 1/6ey
The final product of the Calvin cycle is <span>glucose</span>
