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3 years ago

Simplify- 10x-8y +3x-2y

Mathematics

1 answer:

AleksandrR [38]3 years ago

5 0

Answer:

13x-10y

Step-by-step explanation:

Combine like terms;

10x+3x = 13x

-8y-2y = -10y

So it would give the equation of 13x-10y

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Solve for x.<br><br>2 x - 6 / 4 = 10<br><br>x = [?]

ra1l [238]

Answer:

x = 5.75

Step-by-step explanation:

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3 years ago

I JUST NEED 4 PLS!!!!!!

Alchen [17]

Answer:

Step-by-step explanation:

When doing 4 divided by 2 you get 2. Looking at the sign it is saying 3 is greater than the number we solve for. Since we solved and got 2 we can double check and ask is 3 greater than 2? Yes it is so that would make the statement correct.

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3 years ago

What is the weight of a ring tailed lemur that has a mass of 10 kg? Use w = mg (g = -9.8 m/s^2)

fiasKO [112]

Answer:

None of these

Step-by-step explanation:

Normally, we consider "weight" to be the force due to gravity that an object exerts in the downward direction. It has a positive value equal to the magnitude of "mg". In this instance, it would be ...

... |(10 kg)·(-9.8 N/kg)| = |-98 N| = 98 N

___

However, you're specifically told to use ...

... w = mg

... w = (10 kg)(-9.8 m/s²) = -98 N

This selection is not among those offered.

8 0

3 years ago

What is the unit rate for 14lb for $2.99

Fittoniya [83]

2.99 / 14 = 0.21

Hope I Helped You!!! :-)

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3 years ago

A Regional College uses the SAT to admit students to the school. The university notices that a lot of students apply even though

Aliun [14]

Answer:

0.191 is the probability that a group of 12 randomly selected applicants would have a mean SAT score that is greater than 525 but below the current admission standard of 584.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 500

Standard Deviation, σ = 100

n = 12

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(greater than 525 but 584)

Standard error due to sampling =

$\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{100}{\sqrt{12}}$

$P(525 < x < 584) = P(\displaystyle\frac{525 - 500}{\frac{100}{\sqrt{12}}} < z < \displaystyle\frac{584-500}{\frac{100}{\sqrt{12}}}) = P(0.866 < z < 2.909)\\\\= P(z \leq 2.909) - P(z < 0.866)\\= 0.998 - 0.807 = 0.191 = 19.1\%$

$P(525 < x < 584) = 19.1\%$

0.191 is the probability that a group of 12 randomly selected applicants would have a mean SAT score that is greater than 525 but below the current admission standard of 584.

3 0

3 years ago