Answer:
The system of inequalities is
y\geq 3x-2
y<-(1/5)x+2
Step-by-step explanation:
step 1
Find the equation of the solid blue line
Let
A(0,-2), B(1,1)
Find the slope of AB
m=(1+2)/(1-0)=3
The equation of the line into slope intercept form is equal to
y=mx+b
we have
m=3
b=-2 - ----> the point A is the y-intercept
substitute
y=3x-2 - -----> equation of the solid blue line
The solution of the inequality is the shaded area above the solid line
therefore
The first inequality is
y\geq 3x-2
C(0,2), D(5,1)
step 2
Find the equation of the dashed red line
Let
Find the slope of CD
m=(1-2)/(5-0)=-1/5
The equation of the line into slope intercept form is equal to
y=mx+b
we have
m=-1/5
b=2 ----> the point C is the y-intercept
substitute
y=-(1/5)x+2 -----> equation of the dashed red line
The solution of the inequality is the shaded area below the dashed line
therefore
The second inequality is
y<-(1/5)x+2
The system of inequalities is
y\geq 3x-2
y<-(1/5)x+2
r + 4(r - 3)
<em><u>We'll use the distributive property to simplify this.</u></em>
r^2 - 3r + 4r - 12
<u><em>Combine like terms</em></u>
r^2 + r - 12 is the simplified form.
Answer:
need a diagram to be able to answer
Step-by-step explanation:
Nuke caught the ball after it was thrown 198ft
Answer:
The correct option is 1.
Step-by-step explanation:
it is given that the probability of a randomly selected point on the grid below is in the blue area is 9/16.
In the given grid we have only two colors that are blue and white.
Let A be the event of a randomly selected point on the given grid is in the blue area.
If the randomly selected point on the given grid does not lie in the blue area, it means it lies on white area.
We will calculate P(A'), to find the probability that a randomly selected point is in the white on the grid.
We know that the sum of the probability is 1.
It is given that
Therefore option 1 is correct.
