In order to find zeroes of a function, we will probably want to use our quadratic formula.
-b±√b^2-4(a)(c)/2a
If we know our values, we can plug it in.
Our values:
A=1 (Since there is no number in front of x, it is an assumed 1)
B=17
C=72
Now, We can plug it into our formula.
BE SURE TO PUT PARENTHESIS AROUND ALL TERMS!
-(17)±√(17)^2-4(1)(72)/2(1)
Now we can type it into a calculator!
When we plug it into the formula. It gives us two real solutions (or zeroes) which are represented as:
-8 & -9.
Luckily for us, the diagram already divided this figure into separate polygons. What I will be explaining is basically the addition of the areas of all the separate polygons. The area of the uppermost triangle is:
1/2 x b x h
= 1/2 x 20 x 8
(the base is 20, because in a parallelogram, opposite sides are congruent)
=10 x 8
= 80 in. squared
The next polygon we will be taking the area of is the parallelogram with the base length of 20 and the height of 16.
Area = b x h
= 20 x 16
= 320 in. squared
Now all we have left to do is add the two areas to obtain the total area.
Total Area = 320 + 80 = 400 in. squared
Simplifying -2x + -3y = -7
Solving -2x + -3y = -7
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '3y' to each side of the equation. -2x + -3y + 3y = -7 + 3y
Combine like terms: -3y + 3y = 0 -2x + 0 = -7 + 3y -2x = -7 + 3y
Divide each side by '-2'. x = 3.5 + -1.5y Simplifying x = 3.5 + -1.5y
