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sashaice [31]
3 years ago
9

What is 4.21 rounded to the nearest whole number?

Mathematics
2 answers:
Gre4nikov [31]3 years ago
7 0
The answer is 4 because you round down due to the .2 not being greater than 5
SSSSS [86.1K]3 years ago
3 0

4 because the 21 is less than 50 so it goes straight to the 4
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It’s 11! The answer is D
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In sequences 1,7,13,19, ...., each number is 6 more than the number before it. In the sequences 1,9,17,25,...., each number is 8
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Answer:

I think 17, but I'm not sure.

Step-by-step explanation:

here's what I think.

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14 + 2 + 1

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Eric gets a 7 percent commission for each electronic item he sells .If he sells 3000 worth of elections ,how much commission doe
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Answer:

$210

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Which of the following graphs represents a function with a domain of (-∞, ∞) and a range of (-∞, ∞)?
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The negative infinity for the x coordinate states that the graph should move to the bottom and the y coordinate is positive infinity so that the graph goes up

the first graph is your answer
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The coordinate plane below represents a city. Points A through F are schools in the city. graph of coordinate plane. Point A is
Firlakuza [10]
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.

An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.



Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.

Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.


Part C:
Given that </span><span>Natalie can only attend a school in her designated zone and that Natalie's zone is defined by y < −2x + 2.

To identify the schools that Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.

For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true

For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true

For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false

For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true

For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false

For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
</span>
7 0
3 years ago
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