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seraphim [82]
3 years ago
13

What is the are of this irregular shape?

Mathematics
1 answer:
Basile [38]3 years ago
8 0

Answer:

37 i think sos if its wrong.

Step-by-step explanation:

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A bicycle wheel makes five rotations. the bicycle travels 44.48 ft. Find the diameter of the wheel in inches.
Tema [17]

Answer:

2.42 feet

Step-by-step explanation:

the bicycle wheel rotates 5 times and travels 37.94 feet, then we know that the circumference of the wheel (the outside of the wheel as it touches the ground 5 times around) is 37.94/5 = 7.588

 

Then we use the formula for the circumference of a circle: 2(pi)(radius) = circumference

 

We plug in what we know 2(3.14)(radius) = 7.588 and then solve for the radius

 

We divide 2 from both sides of the equation (3.14)(radius) = 3.794

 

We divide pi from both sides (radius) = 1.208

 

Then the last step, we multiply the radius by 2, because we need the diameter, which is double the radius

 

1.208 * 2 = 2.416 or 2.42 rounded up

 

Final answer = 2.42 feet

7 0
3 years ago
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Which one should I choose
shutvik [7]

Answer:

-32

Step-by-step explanation:

((−4)(4))(2)

=−32

8 0
3 years ago
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WILL MARK BRAINLIEST HELPPP ME
steposvetlana [31]

Answer:

x=47

Step-by-step explanation:

5 0
3 years ago
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in 3 months Us energy giant Enron went from a company with assets of 62bn to a company with depts of 18bn What is the difference
Kaylis [27]
Its just 62-18 so it would be 44bn
7 0
3 years ago
A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
Read 2 more answers
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