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djverab [1.8K]
3 years ago
5

There is a bag filled with 3 blue and 4 red marbles. A marble is taken at random from the bag, the colour is noted and then it i

s not replaced. Another marble is taken at random. What is the probability of getting 2 reds?
Mathematics
1 answer:
Margaret [11]3 years ago
7 0

Answer:

2/7

Altogether there're 7 marbles. Let,probability of getting blue and red marbles be 'B' and 'R' respectively.

In 1st pick

Probability of getting red marble is 4/7

So, there's the probability that the ball in 1st pick may be either blue or red.

So,if the marble is red then we've to eliminate that red marble ( cause,question says so)

Then,in 2nd pick

Probability of getting red ball will be 3/6(<em>if</em><em> </em><em>we</em><em> </em><em>eliminate</em><em> </em><em>that</em><em> </em><em>red</em><em> </em><em>ball</em><em> </em><em>then</em><em> </em><em>the</em><em> </em><em>total</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>marbles</em><em> </em><em>will</em><em> </em><em>also</em><em> </em><em>be</em><em> </em><em>6</em><em>)</em>

Now,

Probability of getting two red will be

(4/7)×(3/6)

=2/7

<em>It</em><em> </em><em>would</em><em> </em><em>be</em><em> </em><em>more</em><em> </em><em>easier</em><em> </em><em>to</em><em> </em><em>do</em><em> </em><em>by</em><em> </em><em>tree</em><em> </em><em>diagram</em><em>.</em><em> </em><em>Since</em><em>,</em><em>I</em><em> </em><em>didn't</em><em> </em><em>find</em><em> </em><em>it</em><em> </em><em>convenient</em><em> </em><em>here</em><em>,</em><em>it</em><em> </em><em>may</em><em> </em><em>be</em><em> </em><em>not</em><em> </em><em>so</em><em> </em><em>much</em><em> </em><em>helpful.But</em><em>,</em><em> </em><em>I</em><em> </em><em>tried</em><em> </em><em>my</em><em> </em><em>best</em><em>.</em><em> </em><em>Hope</em><em> </em><em>you</em><em> </em><em>are</em><em> </em><em>clarified</em><em>.</em>

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