Need help on 5-12! Its geometry.

Are these congruent by SSS, SAS, AAS, ASA? :((

vredina [299]

SAS they both share sides and they also have congruent sides that are marked. They also show that both angles are the same.

4 0

3 years ago

Please Help! 30 POINTS! Given the following three points, find by hand the quadratic function they represent. (−1,−8), (0,−1),(1

ycow [4]

Answer:

(1) B

(2) D

Step-by-step explanation:

(1)

Let the quadratic function be:

$y = ax^{2} + bx + c$

For the point, (0,-1),

$y = ax^{2} + bx + c$

$-1=(a\times0)+(b\times0}+c\\-1=c\\c=-1$

Then the equation is:

$y = ax^{2} + bx -1$

For the point (-1, -8) ,

$y = ax^{2} + bx -1$

$-8=(a\times (-1)^{2})+(b\times -1)-1\\-8=a-b-1\\a-b=-7...(i)$

For the point (1, 2) ,

$y = ax^{2} + bx -1$

$2=(a\times (1)^{2})+(b\times 1)-1\\2=a+b-1\\a+b=3...(ii)$

Add the two equations and solve for a as follows:

$a-b=-7\\a+b=3\\\_\_\_\_\_\_\_\_\_\_\_\_\_\_\\2a = -4\\a = -2$

Substitute a = -2 in (i) and solve for b as follows:

$a-b=-7\\-2-b=-7\\b=5$

Thus, the quadratic function is:

$f(x)=-2x^{2}+5x-1$

The correct option is (b).

(2)

The ordered pairs are:

(5, 7), (7, 11), (9, 14), (11, 18)

Represent them in an XY table as follows:

X : 5 | 7 | 9 | 11

Y : 7 | 11 | 14 | 18

Compute the difference between the Y values as follows:

Diff = 11 - 7 = 4

Diff = 14 - 11 = 3

Diff = 18 - 14 = 4

Now compute the difference between the Diff values:

d = 3 - 4 = -1

d = 4 - 3 = 1

Since the differences between the differences of the y-values is not consistent, the ordered pairs do not represent a quadratic equation.

The correct option is D.

8 0

3 years ago

a square swimming pool has a cement sidewalk around it. The sidewalk is the same width all the way around. The outside perimeter

VLD [36.1K]

Answer:

175 square feet

Step-by-step explanation:

the area of the whole thing is 400 ft. (20 x 20=400)

i got the 20 from the perimeter b/c 20+20+20+20=80

then subtract the area of the pool from 400 to get 175.

6 0

3 years ago

Explain why the terms of the polynomial y2 + 7 are said to be relatively prime.

Georgia [21]

Answer:

The correct answer is because the alternative terms are prime and composite.

Step-by-step explanation:

The given polynomial is $y^{2}$ + 7.

The value of the polynomial when y = 0 is 7.

The value of the polynomial when y = 1 is 8.

The value of the polynomial when y = 2 is 11.

The value of the polynomial when y = 3 is 16.

The value of the polynomial when y = 4 is 23.

The value of the polynomial when y = 5 is 32.

The value of the polynomial when y = 6 is 43.

And so on. Thus the value of the polynomial at alternate values of y are prime. Thus this is why the polynomial is said to be relatively prime.

8 0

3 years ago

Divide n by 5 then add 6

algol [13]

Answer:

n+30/5

Step-by-step explanation:

Simplify n/5

n/5+6

Rewrite the whole as an equivalent fraction

2.1 Add an integer to a fraction

Rewrite the whole as a fraction using 5 as the denominator: 6= 6/1=6×5/5

Equivalent fraction: the fraction thus generated looks different but has the same value as everything.

2.2 sum of the two equivalent fractions add two equivalent fractions that now have a common denominator

Combine the numerators, place the sum or difference over the common denominator, and then reduce to the lowest terms of possible:

n+6×5/5=n+30/5

3 0

3 years ago