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Sergeu [11.5K]
3 years ago
15

If a/2b =3/5 and 4b/3c=1/7, then a/c= I will mark you brainlist whoever get this correct

Mathematics
1 answer:
ioda3 years ago
7 0

Answer:

a/c=2/7 u are welcome thanks for ur help

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3 0
2 years ago
The manufacturing of semiconductor chips produces 2% defective chips. Assume that the chips are independent and that a lot conta
Dmitriy789 [7]

Answer:

a) The approximate probability that more than 25 chips are defective is 0.1075.

b)  The approximate probability of having between 20 and 30 defecitve chips is 0.44.

Step-by-step explanation:

Lets call X the total amount of defective chips. X has Binomial distribution with  parameters n=1000, p =0.02. Using the Central Limit Theorem, we can compute approximate probabilities for X using a normal variable with equal mean and standard deviation.

The mean of X is np = 1000*0.2 = 20, and the standard deviation is √np(1-p) = √(20*0.98) = 4.427

We will work with a random variable Y with parameters μ=20, σ=4.427. We will take the standarization of Y, W, given by

W = \frac{Y-\mu}{\sigma} = \frac{Y-20}{4.427}

The values of the cummmulative distribution function of the standard normal random variable W, which we will denote \phi , can be found in the attached file. Now we can compute both probabilities. In order to avoid trouble with integer values, we will correct Y from continuity.

a)

P(X > 25) = P(X > 25.5)  \approx P(Y>25.5) = P(\frac{Y-20}{4.427} > \frac{25.5-20}{4.427}) =\\P(W > 1.2423) = 1-\phi(1.2423) = 1-0.8925 = 0.1075

Hence the approximate probability that more than 25 chips are defective is 0.1075.

b)

P(20

As a result, the approximate probability of having between 20 and 30 defecitve chips is 0.44.

Download pdf
4 0
3 years ago
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