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Colt1911 [192]
3 years ago
11

This table shows the size, in acres, of four large water parks.

Mathematics
1 answer:
katovenus [111]3 years ago
4 0
Okay organize first and you get

60, 60, 66, 77

even witch means you have to add the middle numbers then divide

60+66=126 divide by two = 63

your answer is B. 63 acres

hope this helped!

:)
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Hoochie [10]
You have to multiply by how many months or boxes and your gonna have 360 and your friend 288
5 0
2 years ago
8x10^6 is how many time as great as 4x10^3
Nataly_w [17]

Answer:

2x10^3

Step-by-step explanation:

Factor the numerator and denominator and cancel the common factors.

7 0
2 years ago
Earth has been charted with vertical and horizontal lines so that points can be named with coordinates. The horizontal lines are
inna [77]
<span>a. The radius of earth is about 6400 kilometers. Find the circumference of a great circle.

Circumference = 2π(radius) = 2π(6400 km) = 40.212,39 km

b. Write an equation for the circumference of any latitude circle with angle theta

As stated, </span><span><span>the length of any parallel of latitude (this is the circumference of corresponding circle) is equal to the circumference of a great circle of Earth times the cosine of the latitude angle</span>:

=> Circumference = 2π*radius* cos(Θ) = 2 π*6400km*cos(Θ) = 40,212.39 cos(Θ)

Answer: circumference = 40,212.39 cos(Θ) km

c. Which latitude circle has a circumference of about 3593 kilometers?

Make </span><span><span>40,212.39 cos(Θ)</span> km = 3593 km

=> cos(Θ) = 3593 / 40,212.39 = 0.08935 => Θ = arccos(0.08935) = 84.5° = 1.48 rad

Answer: 1.48

d. What is the circumference of the Equator? </span>

For the Equator Θ = 0°

=> circumference = 40,213.49cos(0°) km = 40,212.49 km

Answer: 40,212.49 km

7 0
3 years ago
Radio signals travel at a rate of 3x10^8 meters per second how many seconds would it take for a radio signal to travel from a sa
marshall27 [118]

Answer:

1.2x10^-1 seconds

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Let f be the function given by f(x)= (x-1)(x^2-4)/x^2-a. For what positive values of a is f continuous for all real numbers x?
9966 [12]

Answer:

a =1 and a=4.

Step-by-step explanation:

The function is

f(x)=\frac{(x-1)(x^2-4)}{x^2-a}

If we want f(x) to be continuous the denominator needs to be different to 0, otherwise f(x) will be indeterminate.

Now, for a a positive real we have that x=\sqrt{a} will annulate the denominator, i.e

(\sqrt{a})^2-a = a-a = 0. But, if a = 1 we have:

f(x)=\frac{(x-1)(x^2-4)}{x^2-1} = \frac{(x-1)(x^2-4)}{(x-1)(x+1)}=\frac{(x^2-4)}{x+1}

so, the value x=\sqrt{a} = \sqrt{1} = 1 won't annulate the denominator.

Now, for a = 4 we have:

f(x)=\frac{(x-1)(x^2-4)}{x^2-4} = x-1

so, the value x=\sqrt{a} = \sqrt{4} = 2 won't annulate the denominator.

In conclusion, for a=1 or a=1, the function will be continuos for all real numbers, since the denominator will never be 0.

4 0
3 years ago
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