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SOVA2 [1]
3 years ago
14

Please help me !!!

Mathematics
1 answer:
Anastasy [175]3 years ago
4 0
9)~6mn-9m-4n+6=3m(2n-3)-2(2n-3)=(3m-2)(2n-3)\\\\ 10)~a^3+a^2b+ab+b^2=a^2(a+b)+b(a+b)=(a^2+b)(a+b)\\\\ 11)~4r^2s-8rs-3r+6=4rs(r-2)-3(r-2)=(4rs-3)(r-2)\\\\ 12)~x^2y^2-3x^2+2y^2-6=x^2(y^2-3)+2(y^2-3)=\\\\=(x^2+2)(y^2-3)
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stack of mail consists of 8 bills, 10 letters, and 6 advertisements. One piece of mail is drawn at random and put aside. Then a
kozerog [31]

INFORMATION:

We know that:

- stack of mail consists of 8 bills, 10 letters, and 6 advertisements.

- One piece of mail is drawn at random and put aside. Then a second piece of mail is drawn.

And we must find P (both are letters)

STEP BY STEP EXPLANATION:

To find the probability, we need to know that we have two events. First, when one piece of mail is drawn at random and put aside and, second, when a second piece of mail is drawn.

These two events are dependent. If A and B are dependent events, P(A and B) = P(A) • P(B after A) where P(B after A) is the probability that B occurs after A has occurred.

So, first

- Probability of A (the first piece is letter)

P(A)=\frac{favorable\text{ }cases}{total\text{ cases}}=\frac{10}{24}

- Probability of B after A

Since A already occurred and one piece of the mail was drawn (a letter), now in total we would have 9 letter and 23 total pieces

P(B\text{ after }A)=\frac{9}{23}

Finally, replacing in the initial formula

P(A\text{ and }B)=\frac{10}{24}\cdot\frac{9}{23}=\frac{90}{552}=0.1630

Finally, the probability would be 0.1630

ANSWER:

P (both are letters) = 0.1630

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Answer:

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Step-by-step explanation:

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