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3 years ago

Please help and write the steps to fine the answer (ignore the erasings)

Mathematics

2 answers:

zaharov [31]3 years ago

4 0

Answer:

1/50 or 0.02

Step-by-step explanation:

As we can see that, we are given w = 10 and z =2 so to evaluate or calculate the equation, you just have to apply it into the equation:

= (2w^-2)*z^0

= (2*10^-2)* 2^0

We know that any number ^0 would = 1

So in this situation:

= (2*1/100) * 1

= 2/100 * 1

Simplified:

= 1/50 *1

= 1/50 or 0.02

Hope this help you :3

podryga [215]3 years ago

3 0

Answer: 1/50

Step-by-step explanation:

= 2 * 10^-2 * 2^0

= 2 * 1/10^2 * 1 (2^0=1)

= 2/100

= 1/50

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An observer (O) spots a bird flying at a 42° angle from a line drawn horizontal to its nest. If the distance from the observer (

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Read 2 more answers

Quadrilateral ABCD is similar to Quadrilateral EFGH. Diagonal AC has length 7 and diagonal EG has length 13. What is the scale f

olasank [31]

Answer:

$\large \boxed{\text{A. }\dfrac{13}{7}\text{; B. }\dfrac{17}{14} \text{; C. 507 in}^{2}}$

Step-by-step explanation:

A. Scale factor

When you dilate an object by a scale factor, you multiply its line lengths by the same number.

If EF/AB = 13/7, the scale factor is 13/7.

B. Length of EF

$\begin{array}{rcl}\dfrac{EF}{AB} & = & \dfrac{13}{7}\\\\\dfrac{EF}{\frac{17}{26}} & = & \dfrac{13}{7}\\\\EF & = & \dfrac{13}{7}\times\dfrac{17}{26}\\\\ & = &\dfrac{1}{7}\times\dfrac{17}{2}\\\\ & = & \mathbf{\dfrac{17}{14}}\\\end{array}\\\text{The length of EF is $\large \boxed{\mathbf{ \dfrac{17}{14}}}$}$

C. Area of EFGH

If the lengths in a shape are all multiplied by a scale factor, then the areas will be multiplied by the scale factor squared.

ABCD is dilated by a scale factor of 13/7, so its area is dilated by a scale factor of

$\left(\dfrac{13}{7} \right)^{2} = \dfrac{169}{49}$

The area of its dilated image EFGH is

$\text{Area of EFGH} = \text{147 in}^{2} \times \dfrac{\text{169}}{\text{49}} = 3 \times 169\text{ in}^{2} = 507 \text{ in}^{2}\\\\\text{The area of EFGH is $\large \boxed{\textbf{507 in}^{\mathbf{2}}}$}$