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pantera1 [17]
3 years ago
12

What is the solution to the equation -5 p = 24-p?

Mathematics
1 answer:
barxatty [35]3 years ago
4 0
The solution to this equation is p=-6. The explanation is shown.

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Write 10 feet and 4 yards as a fraction in simplest form
S_A_V [24]
⅚. You first find out how many feet are in a yard (three). Then you write the fraction- 10/12. Then you reduce. The number two can evenly go into both of those numbers. Ten divided by two is five. Twelve divided by two is six. So, your final answer is ⅚.
5 0
4 years ago
Ask Your Teacher The circumference of a sphere was measured to be 90 cm with a possible error of 0.5 cm. (a) Use differentials t
SCORPION-xisa [38]

Answer:  

a)  28,662 cm²  max error

    0,0111     relative error

b) 102,692 cm³  max error

   0,004     relative error

   

Step-by-step explanation:

Length of cicumference is: 90 cm

L = 2*π*r

Applying differentiation on both sides f the equation

dL  =  2*π* dr    ⇒  dr = 0,5 / 2*π

dr =  1/4π

The equation for the volume of the sphere is  

V(s) =  4/3*π*r³     and for the surface area is

S(s) = 4*π*r²

Differentiating

a) dS(s)  =  4*2*π*r* dr    ⇒  where  2*π*r = L = 90

Then    

dS(s)  =  4*90 (1/4*π)

dS(s) = 28.662 cm²   ( Maximum error since dr = (1/4π) is maximum error

For relative error

DS´(s)  =  (90/π) / 4*π*r²

DS´(s)  = 90 / 4*π*(L/2*π)²      ⇒   DS(s)  = 2 /180

DS´(s) = 0,0111 cm²

b) V(s) = 4/3*π*r³

Differentiating we get:

DV(s) =  4*π*r² dr

Maximum error

DV(s) =  4*π*r² ( 1/  4*π*)   ⇒  DV(s) = (90)² / 8*π²

DV(s)  =  102,692 cm³   max error

Relative error

DV´(v) =  (90)² / 8*π²/ 4/3*π*r³

DV´(v) = 1/240

DV´(v) =  0,004

3 0
3 years ago
Read 2 more answers
A cutting tool fails due to flank wear while machining. It is observed that the tool life at a cutting speed of 160 m/min is 5 m
Ahat [919]

Answer:

The answer is:

30 minutes.

Step-by-step explanation:

We are given the following information:

at 160 m/min, tool life = 5 min.

at 120 m/min, tool life = 17 min.

This means that as the speed reduced from 160 m/min to 120 m/min, the tool life increased from 5 min. to 17 min, hence the difference between the changes are:

speed = 160 - 120 = 40 m/min

tool life = 17 - 5 = 12 min.

Therefore, it can be concluded that a change of speed of 40 m/min, increases the tool life by 12 min.

40 m/min = 12 min

∴ 1 m/min = 12/40 min.

∴ 100 m/min = 12/40 × 100 = 0.3 × 100 =30 min.

8 0
3 years ago
What is the range of the set {13,5,8,9,15,9}?
erastova [34]
Range=highest number-lowest number

15-5=10
Range=10
8 0
3 years ago
A theater group surveyed 146 audience members after a show and found that 132 of them wanted to see the show again. Find the sta
Sophie [7]

Answer:

0.024

Step-by-step explanation:

Sample size (n) = 146 people

The proportion (p) of people who answered that they would be interested in seeing the show again is:

p=\frac{132}{146}\\ p=0.9041

The standard error for a sample of size 'n' and proportion 'p' is:

SE = \sqrt{\frac{p*(1-p)}{n}}\\SE = \sqrt{\frac{0.9041*(1-0.9041)}{146}}\\ SE=0.024

The standard error for the sample proportion of audience members who want to see the show again is 0.024.

4 0
3 years ago
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