Answer:
a
Step-by-step explanation:
Answer:
Step-by-step explanation:
a^2+b^2=400
a^2=400-b^2
a=sqrt(400-b^2) & -sqrt(400-b^2)
-----------------------------------------------
b^2=400-a^2
b=sqrt(400-a^2) & -sqrt(400-a^2)
Answer:
3
Step-by-step explanation:
2x
8
3y
Convert the mixed numbers to improper fractions, then find the LCD and combine.
Exact Form:
103/14
Decimal Form:
7.35714285
…
7.35714285
…
Mixed Number Form:
7 5/14
Answer: 1/70
Step-by-step explanation:
This is a question that can also be interpreted as what is the probability of having the first number of a phone number to be 8 and the last number of the phone number to also be 8. This answer gives the fraction of the phone numbers that starts with 8 and end with 8.
Since three numbers (0,1,2) cannot start a phone number and we are left to pick from 7 numbers,
then the probability of figure "8" starting phone number = 1/7
Since all 10 numbers can possibly end a phone number,
then the probability of having figure "8" as the last digit of a phone number = 1/10
Hence probability of having "8" as the first and last digit of a phone number = fraction of total telephone numbers that begin with digit 8 and end with digit 8 = 1/7 × 1/10 = 1/70.