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irina1246 [14]
3 years ago
12

Rose can run 4 miles in 56 minutes how many miles does Rosa run if she runs for 42 minutes

Mathematics
2 answers:
sdas [7]3 years ago
5 0

Answer:

<em>At the same rate Rose will run</em><em> 3 miles</em><em> in 42 minutes.</em>

Step-by-step explanation:

Hint- This problem ca be solved using Unitary method.

This Here given that, Rose can run 4 miles in 56 minutes.

i.e Rose in 56 minutes can run 4 miles.

So Rose in 1 minutes can run \dfrac{4}{56} miles.

So Rose in 42 minutes can run \dfrac{4}{56}\times 42=3 miles.

Therefore, if Rose can run 4 miles in 56 minutes, she will run 3 miles in 42 minutes.

kogti [31]3 years ago
4 0
\frac{56}{42} = \frac{4}{x}  then you figure out what you divide 56 by to get 4. which is 14. then you divide 42 by the same number 14.

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Step-by-step explanation:

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3 0
2 years ago
Product A is an 8oz bottle of cough medication that sells for $1.36. Product B is a 16-oz. bottle of cough medication that costs
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Answer:

8 oz bottle

Step-by-step explanation:

1.36/8 = .17

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7 0
3 years ago
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A 1L bag of Normal Saline must infuse over 6 hours using tubing calibrated to deliver 20gtts/mL. How many drops per minute shoul
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Answer:

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Step-by-step explanation:

Give data:

total capacity of bag 1 L = 1000 ml

Duration of infuse 6 hr

quantity at the time delivered is 20 gtts/ml

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4 0
3 years ago
Factor completely. x2−5x−24
Mandarinka [93]

Answer:

(x-8) (x+3)

Step-by-step explanation:

x^2−5x−24

We need two numbers that multiply to negative 24 and add to negative 5

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2 years ago
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An airline knows that 5 percent of the people making reservations on a certain flight will not show up. Consequently, their poli
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Answer:

the probability that there will be a seat available for every passenger who shows up is 0.74

Step-by-step explanation:

if the probability of choosing a passenger that will not show up is 5% , then the probability of choosing a passenger that will show up is 95%.

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Then P(X) follows a binomial probability distribution, since each passenger is independent from others. Thus

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where

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x = number of passengers that will show up

therefore the probability that the number does not exceed the limit of 50 passengers is:

P(X≤50)=  ∑P(X=i)  from i=0 to i=50   =F(50)

where F(x) is the cumulative binomial probability distribution, then from tables:

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therefore the probability that there will be a seat available for every passenger who shows up is 0.74

8 0
3 years ago
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