Question

Consider the polynomial function h(x)=x³+2x-3. Find h(3).

Answer 1

Answer:

$h(3)=30$

Step-by-step explanation:

We have the polynomial:

$h(x)=x^3+2x-3$

$h(3)$ means that we have to replace in the polynomial $h(x)$ with $x=3$.

Then,

$h(x)=x^3+2x-3\\h(3)=3^3+2.3-3\\h(3)=27+6-3\\h(3)=27+3\\h(3)=30$

We obtain that the polynomial h(x) with x=3 is 30.

$h(3)=30$