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svet-max [94.6K]
2 years ago
13

Which of the following is a true statement?

Mathematics
1 answer:
aev [14]2 years ago
4 0

Answer:

13/15 > 4/5 is a true stament.

Step-by-step explanation:

The left side is 0.86 repeating turned into a decimal. which means 0.86 is greater than the right which the right is 0.8 turned into a decimal. which in this case this means that the given stament is always true.

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Help me pls what is 3(3)+1
drek231 [11]

Answer:its 10 :)

Step-by-step explanation:

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2 years ago
What integers are plotted on the number line below?
Nonamiya [84]

The correct answer would be D because if there are points at -8 and -2, those are the numbers that are plotted.

4 0
3 years ago
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The store offers a 40% discount. If the regular price of a t-shirt is $21, what is the discount price?
goldenfox [79]

Answer:

$8.40

Step-by-step explanation:

to find discount you use part=%(whole) so you are looking for your part but know the % and whole so you do x=40%(21) and 40%, or 0.4, times 21 is 8.4 so thats your part, 8.4 is 40% of 21 and thats how much youll pay

3 0
2 years ago
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Express this number in scientific notation. <br> 0.0013?
NeX [460]

Answer:

1.3*10^-3

Step-by-step explanation:

When using scientific notation, if you are moving to the left it is a positive exponent. If you are moving to the right it is a negative exponent. since we moved the decimal point to the right, the exponent will be negative.

3 0
3 years ago
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Pre-calc questions (trignometry)
miv72 [106K]

Answer:  (1a) 250°  (1b) 70°    (2) see below

<u>Step-by-step explanation:</u>

1a) -110 + 360 (one rotation clockwise) = 250°

1b) 430 - 360 (one rotation counterclockwise) = 70°

2) sec Ф = -8/5    in Quadrant III

Quadrant III identifies that both sin (y) and cos (x) are negative.

sec = r/x --> r = 8, x = -5, and y = -√39

(Use Pythagorean Theorem x² + y² = r² to solve for y)

\sin\theta=\dfrac{y}{r}=\dfrac{-\sqrt{39}}{8}              \csc\theta=\dfrac{r}{y}=\dfrac{-8}{\sqrt{39}}  rationalized = \dfrac{-8\sqrt{39}}{39}

\cos\theta=\dfrac{x}{r}=\dfrac{-5}{8}                  \sec\theta=\dfrac{r}{x}=\dfrac{-8}{5}  (GIVEN)

\tan\theta=\dfrac{y}{x}=\dfrac{\sqrt{39}}{5}              \cot\theta=\dfrac{x}{y}=\dfrac{-5}{-\sqrt{39}}  rationalized = =\dfrac{5\sqrt{39}}{39}

NOTE THAT YOU ARE ALLOWED A MAXIMUM OF 3 QUESTIONS PER POST.  Please repost #3 and #4 as a different question and I will answer them.

8 0
2 years ago
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