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3 years ago

11

Want a challenge, well take a look at these pics and see if you can answer them. :D Good luck :]

2 answers:

ANTONII [103]3 years ago

7 0

Welp someone already answered and I have to answer questions so I can get someone to help me with my hw but good luck bro/ ma’am :)

stealth61 [152]3 years ago

3 0

What level math courses are these if you don’t mind me asking? Enjoy the answers :’)

Part 1A)

Let Y be the number of tickets sold.

Y = 2.5X

Part 1B)

0=0
2=5
4=10
6=15

Part 1C)

You have to do the graph independently.

Part 1D)

There were 10 tickets sold and $25 were made.

Part 2A)

Holi earns more, 0.50¢ / hour

Part 2B)

Let X be the hours worked
Let Y be the total pay

Y = 8.75X

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Julli [10]

Answer:

The values of 'x' are -1.2, 0, 0, $-4i$ or $4i$ .

Step-by-step explanation:

Given:

The equation to solve is given as:

$5x^5+6x^4+80x^3+96x^2=0$

Factoring $x^2$ from all the terms, we get:

$x^2(5x^3+6x^2+80x+96)=0$

Now, rearranging the terms, we get:

$x^2(5x^3+80x+6x^2+96)=0$

Now, factoring $5x$ from the first two terms and 6 from the last two terms, we get:

$x^2(5x(x^2+16)+6(x^2+16))=0\\x^2(x^2+16)(5x+6)=0$

Now, equating each factor to 0 and solving for 'x', we get:

$x^2=0\\x=0\ and\ 0\\\\5x+6=0\\x=\frac{-6}{5}=1.2\\\\x^2+16=0\\x^2=-16\\x=\sqrt{-16}=\pm 4i$

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Therefore, the values of 'x' are -1.2, 0, 0, $-4i$ or $4i$ .

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Step-by-step explanation:

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(x,y)→(x+5,y+2).

Then the image triangle A'B'C' has vertices A'(-1,1), B'(2,-1) and C'(4,0).

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(x,y)→(-y,-x).

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