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Stels [109]
3 years ago
13

What is the quantum number set of the ground-state electron that is found in helium (He) but not in hydrogen (H)

Chemistry
1 answer:
valentina_108 [34]3 years ago
7 0
(1,0,0,-1/2)
Ghhbbhgvivucyydydyfycycycyccucvvvuvuvuvubu
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When a writer uses “common knowledge” in an essay, why does it NOT require a citation nor is it considered plagiarism?
krek1111 [17]
Plagiarism is when you just copy exactly what someone else says, without their permission, or without citing where you got it from. 
Common knowledge should be your own words. unless you take it from somewhere else, it doesnt need anything.
6 0
3 years ago
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I WILL MARK THE BRAINLYEST AND GIVE YOU 100 POINTS
yuradex [85]

4 moles

64 grams of oxygen contains 4 moles

3 0
3 years ago
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What pressure will cause 1.70 atm and 300.0°C to increase to 350.0°C ? Assume constant volume. Reminder : Kelvin = 273 + °C *
mestny [16]

Answer: 1.85 atm

Explanation:

Initial pressure P1 = 1.70 atm

Initial temperature T1 = 300.0°C

Convert temperature in Celsius to Kelvin i.e (273 + 300.0°C) = 573K

Final pressure P2 = ?

Final temperature T2 = 350.0°C

(273 + 350.0°C) = 623K

Mathematically, pressure law states the pressure (p) of a gas is directly proportional to the absolute temperature (T).

i.e Pressure ∝ Temperature.

P1/T1 = P2/T2

1.70 atm/573K = P2/623K

P2 = (1.70 ATM x 623K) / 573K

P2 = 1059.1/573

P2 = 1.85 atm

Thus, the 1.85 atm of pressure is required.

5 0
3 years ago
Substance A and B are chemically exactly the same. The molecules in substance A move much faster and are less ordered than the m
Elina [12.6K]

Answer:

substance A is a liquid, while substance B is a liquid or gas

7 0
3 years ago
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Nicotine (C10H14N2), a plant alkaloid, is an oily liquid that makes up between 0.6 to 3% of a cigarettes mass. Contact with the
Pepsi [2]

There are 1.66 \times 10^{22} molecules in 1 gram of nicotine.

<u>Explanation</u>:

Nicotine is an organic compound with the chemical formula of C_{10} H_{14} N_{2}

Given  the mass of nicotine = 4.50 g

Molecular mass of Nicotine = 162.23 g/mol

Moles of a compound = given mass / molar mass of the compound

                                     = \frac{4.50}{162.23}  = 0.0277

The Number of molecules of compound:

Moles \times Avogadro number = 0.0277 \times 6.023 \times 10^{23}

                                             = 1.66 \times 10^{22} molecules.

There are 1.66 \times 10^{22} molecules in 1 gram of nicotine.

4 0
3 years ago
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