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Dmitry_Shevchenko [17]
3 years ago
6

How many acidic H+ ion is given by H3BO3 in aqueous solution?? ...?

Chemistry
1 answer:
notka56 [123]3 years ago
7 0
Boric acid, H3BO3, in aqueous solution would only give out one H+ ion. As it is also produce OH ion and by hydrolysis it produces one proton. <span>All the boron compounds (BX3) are having only 6 valence electrons in it and should follow the octet rule by taking another electron.</span>
 
B(OH)3 + 2 H2O → B(OH)4− + H3O
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Which of the following factors would reduce the yield of a reaction?
NikAS [45]

The products being more stable than the reactants is the factor which would reduce the yield of a reaction and is denoted as option B under standard conditions.

<h3>What is a Chemical reaction?</h3>

This is the process in which one or more substances which are referred to as reactants are converted into new substances which we call the products.

A chemical reaction involves atoms exhibiting different bond formation so as to ensure they acquire an octet configuration and promotes proper stability of the products.

When the products are more stable than the reactants it means it is unable to form other products thereby decreasing the yield which is why it was chosen as the most appropriate choice.

Read more about Chemical reaction here brainly.com/question/11231920

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3 0
2 years ago
For the complete combustion of 47 g of gasoline (octane, C8H18) , the mass of oxygen consumed is
aleksklad [387]

Answer: d) 164.9 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}     \text{Moles of octane}=\frac{47g}{114g/mol}=0.412moles

The balanced chemical reaction is:

2C_8H_{18}(l)+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(g)  

According to stoichiometry :

2 moles of C_8H_{18} require = 25  moles of O_2

Thus 0.412 moles of C_8H_{18} will require=\frac{25}{2}\times 0.412=5.15moles  of O_2

Mass of O_2=moles\times {\text {Molar mass}}=5.15moles\times 32g/mol=164.9g

Thus 164.9 g of oxygen is consumed.

4 0
3 years ago
How might the structure of an atom be modeled
Sergio [31]

Answer:

you can explore the structure of atoms as you add protons, neutrons, or electrons to a model and the name of the element you have created

Explanation:

8 0
3 years ago
What is another term for a responding variable
Burka [1]
There are different types of variables in experiments. The manipulated variable is the one you change. The controlled variable is the one you control. The responding variable is the variable that changes as you change the manipulated variable, or the one you are expecting to change.
5 0
3 years ago
The electrolysis of water forms H2 and O2. 2H2O 2H2 + O2 What is the percent yield of O2 if 10.2 g of O2 is produced from the de
BigorU [14]

<u>Answer:</u> The percent yield of oxygen gas is 67.53 %.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of water = 17.0 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{17.0g}{18g/mol}=0.944mol

For the given chemical equation:

2H_2O\rightarrow 2H_2+O_2

By Stoichiometry of the reaction:

2 moles of water produces 1 mole of oxygen gas

So, 0.944 moles of water will produce = \frac{1}{2}\times 0.944=0.472moles of oxygen gas

Now, calculating the mass of oxygen gas from equation 1, we get:

Molar mass of oxygen gas = 32 g/mol

Moles of oxygen gas = 0.472 moles

Putting values in equation 1, we get:

0.472mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.472mol\times 32g/mol)=15.104g

To calculate the percentage yield of oxygen gas, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of oxygen gas = 10.2 g

Theoretical yield of oxygen gas = 15.104 g

Putting values in above equation, we get:

\%\text{ yield of oxygen gas}=\frac{10.2g}{15.104g}\times 100\\\\\% \text{yield of oxygen gas}=67.53\%

Hence, the percent yield of oxygen gas is 67.53 %.

7 0
4 years ago
Read 2 more answers
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