Which of the sets of ordered pairs represents a function? (1 point) A = {(2, 7), (1, −5), (7, 2), (2, −9)} B = {(5, 3), (−2, −9)
Neporo4naja [7]
Answer:
its B
Step-by-step explanation:
i was taught to do functions by lining up the xs on one side and the ys on the other(if they repeat only put the number once) then draw lines to the pairs. no x value can have two y values.
Option a:
sin A for the triangle is
.
Solution:
The given triangle is a right triangle.
The adjacent side to angle A is AC.
The opposite side to angle A is BC.
Hypotenuse is AB.
AC = 8, BC = 6 and AB = 10.
Using trigonometric ratio formulas,



Divide both numerator and denominator by 2, we get


Hence sin A for the triangle is
.
Option a is the correct answer.
A) 20.93%
B) 20%
C) 59.07%
Explanation
A) The total area of the rectangle is 6(10) = 60 ft². The area of the circle is 3.14(2²) = 12.56. This makes the probability of hitting the circle is 12.56/60 = 20.93%.
B) The total area of the rectangle is 60. The area of the trapezoid is 1/2(2+4)(4) = 12 ft². This makes the probability of hitting the trapezoid 12/60 = 20%.
C) The areas of the circle and trapezoid together are 12+12.56 = 24.56. This makes the rest of the area 60-24.56 = 35.44. This gives us the probability of not hitting the circle or trapezoid 35.44/60 = 59.07%
Answer:
x=pi/3 + 2pi*k
x=2pi/3+2pi*k
Step-by-step explanation:
sin(x)=sqrt(3)/2
This happens twice in the first rotation on our unit circle.
It happens in the first quadrant and in the second quadrant. Third and fourth quadrants are negative for sine.
So we are looking for when the y-coordinate on the unit circle is sqrt(3)/2.
This is at pi/3 and 2pi/3.
So we can get all the solutions by adding +2pi*k to both of those. This gives us a full rotation about the circle any number of k times. k is an integer.
So the solutions are
x=pi/3 + 2pi*k
x=2pi/3+2pi*k