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2 years ago

Explain why n > 5 and 5 > n are not equivalent.

Mathematics

2 answers:

xeze [42]2 years ago

6 0

Answer:

In n > 5 the values of n have to be GREATER THAN 5 so n can equal anything 6 or higher

In 5 > n the 5 is GREATER than the values of n, so the values of n are LESS THAN 5. The values of n can equal anything 4 or less.

Step-by-step explanation:

klemol [59]2 years ago

4 0

Answer:

yes it is not b/c

Step-by-step explanation:

if n is >5 ,5 is < n

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alexira [117]

The answer would be A and C.

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5 0

3 years ago

The figure shown is a kite. What is the x-coordinate of point P?

tresset_1 [31]

The answer to the above question can be determined as -

Let the point on the left side of P be Q, thus coordinates of Q are (a,1) and point on the right side of P be R, thus coordinates of R will be, (a+4, 1).

Now, it given that, between x coordinates of Q and R is 4, and it can be seen that they are getting divided into half.

So, the x coordinate of P will be - a + $\frac{4}{2}$ i.e. a + 2

<u>Thus, the x coordinate of P will be a +2.</u>

6 0

2 years ago

Read 2 more answers

1. The networking organization you joined is throwing a party. You are in charge of buying the chips, which cost $2.50 per bag a

lapo4ka [179]

Answer:

Option d :18 bags of chips and 6 jars of salsa

Step-by-step explanation:

Given : The networking organization you joined is throwing a party. You are in charge of buying the chips, which cost $2.50 per bag and salsa, which costs $4 per jar. The chips & salsa budget you are given totals $60.

Inequality : $2.5x+4y\leq 60$

Solution :

x represents chips

y represents salsa

Option a: 10 bags of chips and 2 jars of salsa

so, x = 10 and y =2

Putting values in inequality

$2.5(10)+4(2)\leq 60$

$25+8\leq 60$

$33\leq 60$

Hence it is correct.

Option b : 20 bags of chips and 2 jars of salsa

so, x = 20 and y =2

Putting values in inequality

$2.5(20)+4(2)\leq 60$

$50+8\leq 60$

$58\leq 60$

Hence it is correct.

Option c : 14 bags of chips and 5 jars of salsa

so, x = 14 and y =5

Putting values in inequality

$2.5(14)+4(5)\leq 60$

$35+20\leq 60$

$55\leq 60$

Hence it is correct.

Option d :18 bags of chips and 6 jars of salsa

so, x = 18 and y =6

Putting values in inequality

$2.5(18)+4(6)\leq 60$

$45+24\leq 60$

$69\geq 60$

Hence it is not correct since it violates the inequality

4 0

3 years ago

Read 2 more answers

Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

8 0

2 years ago

Radius = 11 cm.; Height = 10 cm.

Fittoniya [83]

Answer:

$3801.32 {cm}^{3}$

Step-by-step explanation:

$V=π {r}^{2} h \\ =π· {11}^{2} ·10 \\ ≈3801.3271$

5 0

3 years ago