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Nutka1998 [239]
3 years ago
5

Hey can someone please help explain and answer this 1 question. There's a picture. Thank you!

Mathematics
1 answer:
Vilka [71]3 years ago
6 0
The graph shown in the picture is a hyperbola. It can be shown that the center lies on the line of symmetry. In this case, it can be seen that center of the hyperbola is at (3,-5). A hyperbola has an equation of x^2/a - y^2/b =1. a and b are the units between the two curves. a and b are both equal to 4. SInce the center is (3,-5), the equation of the parabola is  (<span>x-3)^2/4 - (y+5)^2/4 =1.</span>
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Someone please help me
Tems11 [23]
The answer is 43. What I did was I added all the numbers together, and since they wanted the area, and to find the area you multiply TWO numbers together, I multiplied the sum by 2 and I got 43. Hope this helps!

Aye Sir!
4 0
3 years ago
Which expression has the same value as the one below?<br> 38 + (-18)
Fittoniya [83]

Answer:

D

Step-by-step explanation:

38+(-18) can be changed to 38-18 and the answer will still be the same

8 0
2 years ago
Kathy was building a bed for her dollhouse. She used her bed, which is 3 feet × 5 feet, as a guide. She scaled down the dimensio
Anna11 [10]
We know, final dimension = initial dimension * dilation factor
= 3 * 1/5 = 0.6
& 6 * 1/5 = 1

In short, Your Answer would be Option D) <span>0.6 ft × 01 ft

Hope this helps!</span>
4 0
2 years ago
Read 2 more answers
What is the probability of rolling a number greater than or equal to 9 with the sum of two dice, given that at least one of the
olga55 [171]
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
6 0
2 years ago
2. In the diagram below, secants PT and PU have been drawn from exterior point P such that the four arcs
scoundrel [369]

Answer:

(a) x = 30°

(b) mRS =  30°

mST =  120°

mTU  = 120°

mUR = 90°

Step-by-step explanation:

(a) In the picture attached, the diagram is shown.

Given that m arc RS = x, from the ratios:

m arc ST = 4x

m arc TU = 4x

m arc UR = 3x

The addition of the four arcs must be equal to 360°, then:

x + 4x + 4x + 3x = 360°

12x = 360°

x = 360°/12 = 30°

(b) m arc RS = x = 30°

m arc ST = 4x = 4*30° = 120°

m arc TU = 4x = 4*30° = 120°

m arc UR = 3x = 3*30° = 90°

8 0
3 years ago
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