GEOMETRY please help soon due in an hour
1 answer:
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Easy
the easiest way is to imagine that you have a rectangle with a corner cut off
the area of the figure=area of rectangle-area cut off
area that was cut off was a triangle
area of rectangle=length times width
area of triangle=1/2base times height
so we draw imaginary lines like in attachment
find area of rectangle
legnth=9 inch
width=9 inch
area=9 times 9=81 in^2
triangle
the top part is ?+5=9, so the base of triangle=4
the side is ?+4=9, so the base is 5
area=1/2 times 4 times 5=10 in^2
area=rectangle-triangle
area=81-10=71 in^2
the easiest way is to imagine that you have a rectangle with a corner cut off
the area of the figure=area of rectangle-area cut off
area that was cut off was a triangle
area of rectangle=length times width
area of triangle=1/2base times height
so we draw imaginary lines like in attachment
find area of rectangle
legnth=9 inch
width=9 inch
area=9 times 9=81 in^2
triangle
the top part is ?+5=9, so the base of triangle=4
the side is ?+4=9, so the base is 5
area=1/2 times 4 times 5=10 in^2
area=rectangle-triangle
area=81-10=71 in^2
Answer:
1 - c
2 - A
Step-by-step explanation:
Hey There!
So for the first one we are given the dimensions of a rectangular prism and they want us to find the volume
Remember to find the volume we use the equation
V = length x width x height
so we just plug in the values
v = 2.6 x 2.1 x 3.9 = 21.294
the closest is 20 so C is your answer
For the second one we are given a triangular prism
and they want us to find the volume
b = base (10.3)
l = length (4)
h = height (7)
7x4=28
28x10.3=288.4
then we divide by 2
288.4/2=144.2
so your selected answer is correct