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Ulleksa [173]
3 years ago
11

What is 6.892 as a fraction

Mathematics
2 answers:
Doss [256]3 years ago
6 0

6.892

.892 = 892/1000

Answer: 6_892/1000

You can reduce 892/1000 if needed. I'll let you do that.

sweet-ann [11.9K]3 years ago
3 0

Answer:

6 223/250

Step-by-step explanation:

Rewrite the decimal number as a fraction with 1 in the denominator

6.892=6.8921

Multiply to remove 3 decimal places. Here, you multiply top and bottom by 103 = 1000

6.8921×10001000=6892/1000

Find the Greatest Common Factor (GCF) of 6892 and 1000, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 4,

6892÷41000÷4=1723/250

Simplify the improper fraction,

=6 223/250

In conclusion,

6.892=6 223/250

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the slope of the line is 2

4 0
3 years ago
Mai is flying a plane at an altitude of 1600 ft. She sights a stadium at an angle of
LekaFEV [45]

Answer:

2,789ft

Step-by-step explanation:

The set up will give a right angled triangle.

The altitude will be the opposite side = 1600 ft

The angle of depression = 35°

approximate direct distance to the stadium is the hypotenuse of the trisngle= x

Using the SOH trig identity to get the distance

sin 35 = opp/hyp

sin 35 = 1600/x

x = 1600/sin35

x = 1600/0.5736

x = 2,789.4ft

Hence mai’s approximate direct distance to the stadium is 2,789ft

4 0
3 years ago
If k(x) = 5x - 6, which<br> expression is equivalent to (k + k)(4)?
kogti [31]
28! hope this helps, you just plug in 4 for x, and then multiply by two.
3 0
3 years ago
Read 2 more answers
What's the answer to 243.875 to nearest tenth,hundredth, ten,and hundred
trapecia [35]
Tenth: 243.9
Hundredth: 243.88
Ten: 240
Hundred: 200
3 0
3 years ago
Read 2 more answers
Simplify: cos2x-cos4 all over sin2x + sin 4x
GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

6 0
3 years ago
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