Answer:
![\[y=-2x+13\]](https://tex.z-dn.net/?f=%5C%5By%3D-2x%2B13%5C%5D)
Step-by-step explanation:
Equation of the line CD is given as ![\[y=-2x-2\]](https://tex.z-dn.net/?f=%5C%5By%3D-2x-2%5C%5D)
Slope of the line CD = -2
Slope of the line parallel to CD = -2
Equation of the line parallel to CD is given by ![\[y=mx+c\]](https://tex.z-dn.net/?f=%5C%5By%3Dmx%2Bc%5C%5D)
![\[y=-2x+c\]](https://tex.z-dn.net/?f=%5C%5By%3D-2x%2Bc%5C%5D)
But this line passes through (4,5)
Substituting the values in the equation:
![\[5=-2*(4)+c\]](https://tex.z-dn.net/?f=%5C%5B5%3D-2%2A%284%29%2Bc%5C%5D)
=> ![\[c=5+8=13\]](https://tex.z-dn.net/?f=%5C%5Bc%3D5%2B8%3D13%5C%5D)
So the overall equation of the parallel line is given by
Height is 1 1/24 unit.
Given:
volume = 5/24 unit³
base area = 1/5 unit²
Rectangular prism:
volume = length * width * height
base area = length * width
Volume = base area * height
height = volume / base area
h = 5/24 ÷ 1/5
h = 5/24 * 5/1 = 5*5 /24*1 = 25/24 = <span>1 1/24 unit</span>
Answer:
216 cm²
Step-by-step explanation:
Applying,
V = lwh..................... Equation 1
Where V = volume of the cubiod, l = length of the base, width of the base, h = heigth of the cubiod.
From the question,
Since the base of the cubiod is squared,
Therefore,
w = l = 4 cm, V = 400 cm³
Substitute these values into equation 1
400 = 4×4×h
h = 400/(4×4)
h = 25 cm
A = lw+lh+wh.................. Equation 1
Where A = surface area of the cuboid.
Given: l = 4 cm. w = 4 cm, h = 25 cm
Substitute these values into equation 1
A = (4×4)+(4×25)+(4×25)
A = 16+100+100
A = 216 cm²
Answer:
324ft^2
Step-by-step explanation:
rectangle: 22ft X 12ft = 264ft^2
trapazoid: 1/2(22+8)4 = 60ft^2
264 + 60 = 324ft^2
hope this helped!! :D
tell me if you need further explaination!
