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3 years ago

1. A principal of $6,325 is placed in an account that earns 3.5% interest. If the interest is

Mathematics

1 answer:

valkas [14]3 years ago

4 0

Answer:

4 years and 0.035 yw

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8) How many solutions does the following<br> equation have?<br> 0 = 9x2 - 6x + 1

sweet [91]

I’m guessing it’s 9x^2 -6x + 1 but this is basically just one. (1/3,0) use desmos if you’re curious

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2 years ago

HELP ASAP MARKING AS BRINLIST

weeeeeb [17]

Answer:

Because they are equal (Right angle)

Two figures or objects are congruent if they have the same shape and size, or if one has the same shape and size as the mirror image of the other.

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3 years ago

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Solve and type in a different form by using the given theorems of logarithms

scoray [572]

$\log\left(\frac{10}{y}\right) = \log(10) - \log(y)$

The general rule is

$\log\left(\frac{A}{B}\right) = \log(A) - \log(B)$

Other log rules are

$\log(AB) = \log(A) + \log(B)$

$B\log(A) = \log(A^B)$

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3 years ago

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katovenus [111]

Answer:

The car gets 30 miles to the gallon. After the car has traveled 80 miles , 2 2/3 gallons have been consumed.

Step-by-step explanation:bro trust me

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3 years ago

The rectangle below has an area of 1 8 x 3 18x 3 square meters and a length of 2 x 2 2x 2 meters.

motikmotik

Answer:

$\text{The width of rectangle}=9x\text{ meters}$

Step-by-step explanation:

We have been given that the rectangle has an area of $18x^3$ square meters and a length of $2x^{2}$ . We are asked to find the width of rectangle.

Since we know that area of a rectangle is width times length of the rectangle, so we can find width of our given rectangle by dividing given area by length of rectangle.

$\text{Area of rectangle}=\text{Width of rectangle *Length of the rectangle}$

$\frac{\text{Area of rectangle}}{\text{Length of rectangle}}=\frac{\text{Width of rectangle *Length of the rectangle}}{\text{Legth of rectangle}}$

$\text{The width of rectangle}=\frac{\text{Area of rectangle}}{\text{Length of rectangle}}$

Upon substituting our given values in above formula we will get,

$\text{The width of rectangle}=\frac{18x^3\text{ meter}^2}{2x^2\text{ meters}}$

$\text{The width of rectangle}=\frac{9x^3\text{ meters}}{x^2}$

Using exponent rule for quotient $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\text{The width of rectangle}=9x^{3-2}\text{ meters}$

$\text{The width of rectangle}=9x^{1}\text{ meters}=9x\text{ meters}$

Therefore, width of our given rectangle will be 9x meters.

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3 years ago