Answer:
no solutions
Step-by-step explanation:
b-9-b=-18
Combine like terms
0b -9 = -18
-9 = -18
This is never true so there are no solutions
You want to find
; that is, given that you randomly choose from the pool of women, the probability that she does not exercise.
By definition of conditional probability,
![P(\text{no exercise}\mid\text{woman})=\dfrac{P(\text{no exercise AND woman})}{P(\text{woman})}](https://tex.z-dn.net/?f=P%28%5Ctext%7Bno%20exercise%7D%5Cmid%5Ctext%7Bwoman%7D%29%3D%5Cdfrac%7BP%28%5Ctext%7Bno%20exercise%20AND%20woman%7D%29%7D%7BP%28%5Ctext%7Bwoman%7D%29%7D)
496 of the total 1026 people are woman, and 341 of the 1026 people are women and do not exercise, so
![P(\text{no exercise}\mid\text{woman})=\dfrac{\frac{341}{1026}}{\frac{496}{1026}}=\dfrac{341}{496}=0.6875\approx0.688](https://tex.z-dn.net/?f=P%28%5Ctext%7Bno%20exercise%7D%5Cmid%5Ctext%7Bwoman%7D%29%3D%5Cdfrac%7B%5Cfrac%7B341%7D%7B1026%7D%7D%7B%5Cfrac%7B496%7D%7B1026%7D%7D%3D%5Cdfrac%7B341%7D%7B496%7D%3D0.6875%5Capprox0.688)
A simpler way of doing this is to look at what's called the marginal distribution of women in the table. Basically this comes down to ignoring all but the data pertaining to the women. There's a total of 496 women, and 341 of them do not exercise. So the probability that a given woman does not exercise is 341/496.
This would vary on the perspective of the solver. In this case, the solution would be
A A A B B B B C C C
A A A B B B B C C C
A A A B B B B C C C
A A A B B B B C C C
A A A B B B B C C C
A A A B B B B C C C
A A A B B B B C C C
A A A B B B B C C C
A A A B B B B C C C
A A A B B B B C C C
such that Employee A would constitute 30%, Employee B would constitute 40% and Employee C would constitute 30% of the work.
I hope I was able to answer your question. Have a good day.
Answer:
The probability that a randomly selected boy in secondary school can run the mile in less than 302 seconds is 0.0107
Step-by-step explanation:
Consider the provided information.
It is given that mean is 440 seconds and standard deviation is 60 seconds.
z factor for less than 302 seconds would be: ![z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
z = (302 - 440) / 60 = -2.3
The probability of getting a z factor of less than -2.3 = 0.0107 approximately.
looking up in the z-table for a z factor of -2.3.
The probability of a student running the mile in less then 302 seconds would be 0.0107.
Hence, the probability that a randomly selected boy in secondary school can run the mile in less than 302 seconds is 0.0107
Answer:total amount of money that he should pay if he has not used his duty free exemption is $98
Step-by-step explanation:I did this before