All categories

3 years ago

What is the area? Pls help! Will give brainliest if possible!

Mathematics

2 answers:

dsp733 years ago

3 0

Answer:

9 1/3

Step-by-step explanation:

2 x 4 = 8

1/3 + 1/3+ 1/3+ 1/3= 1 1/3 + 8 = 9 1/3

Hope this helps

Sergeu [11.5K]3 years ago

3 0

4 2/3 I think

Step-by-step explanation:

Because there's 4 sides. So we multiply the 2 sides to get the area. 2 1/3 x 2 = 4 2/3!

You might be interested in

For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

5 0

3 years ago

How many terms are in the expression shown below?<br> 5x + 3y - 6

tatiyna

Answer: 3 terms

Step-by-step explanation:

each term is separated by the plus or minus symbol

8 0

3 years ago

Read 2 more answers

Each square is one square unit. Sienna uses the same square units to draw a 6 x 2 rectangle and says that it has the same area a

Grace [21]

Answer:

Yes, Sienna is correct because 6 times 2 is 12 and 3 times 4 is 12.

3 0

3 years ago

The scatter plot shows a hiker's elevation above sea level during a hike from the base to the top of a mountain. The equation o

irakobra [83]

Answer:

2232 for 170 minutes

Step-by-step explanation:

4 0

2 years ago

Suppose (1,19) is on the graph of y = f (x). Which of the following points lies on the graph of the transformed function y = f(1

o-na [289]

Answer:

(5,19) lies on the graph of the transformed function y = f(1/5x)

Step-by-step explanation:

Suppose (1,19) is on the graph of y = f (x)

the graph of the transformed function y = f(1/5x)

$y=f(\frac{1}{5}x)$

1/5 is multiplied with x in f(x)

1/5 is less than 1 so there will be a horizontal stretch in the graph by the factor of 1/5

To make horizontal stretch we change the point

f(x)=f(bx) then (x,y) --->( x/b,y)

We divide the x coordinate by the fraction 1/5

(1,19) ----> $(\frac{1}{\frac{1}{5}} , 19)= (5,19)$

So (5,19) lies on the graph of the transformed function y = f(1/5x)

8 0

3 years ago