If there are 12, and nine have chocolate, subtract 9 from 12. You will get 3, so you will get 3/12.
I think a is (8,-8)
B) (0,8)
Answer:
-675/15
Step-by-step explanation:
The problem isn't even complete
Answer:
See below
Step-by-step explanation:
The initial ordered-pairs are 
We have a rotation of 90 degrees counterclockwise with respect to origin
Note. Previously the points were
After the rotation, we have
Thus, 
Then shifting horizontally to the right 2 units, we get ΔA'B'C'
Thus,
Answer:
There is no solution to this problem.
Step-by-step explanation:
The 1 digit number cannot be 1, since there would be no remainder.
The 1 digit number cannot be 2, since the remainder could be 0 or 1.
The 1 digit number cannot be 3, since the remainder could be 0, 1, or 2.
So, the 1 digit number must be greater than 3. Let's start with 4. Since the quotient is 307 (remainder 3), 4 x 307 is already more than 3 digits.
