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vova2212 [387]
3 years ago
13

3. The area of a rectangular deck, in square meters, is given by the polynomial 40p2 + 24p.

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
4 0

Answer:

Length = 5p + 3

Perimeter = 26p + 6

Step-by-step explanation:

Given

Area = 40p² + 24p

Width = 8p

Solving for the length of deck

Given that the deck is rectangular in shape.

The area will be calculated as thus;

Area = Length * Width

Substitute 40p² + 24p and 8p for Area and Width respectively

The formula becomes

40p² + 24p = Length * 8p

Factorize both sides

p(40p + 24) = Length * 8 * p

Divide both sides by P

40p + 24 = Length * 8

Factorize both sides, again

8(5p + 3) = Length * 8

Multiply both sides by ⅛

⅛ * 8(5p + 3) = Length * 8 * ⅛

5p + 3 = Length

Length = 5p + 3

Solving for the perimeter of the deck

The perimeter of the deck is calculated as thus

Perimeter = 2(Length + Width)

Substitute 5p + 3 and 8p for Length and Width, respectively.

Perimeter = 2(5p + 3 + 8p)

Perimeter = 2(5p + 8p + 3)

Perimeter = 2(13p + 3)

Open bracket

Perimeter = 2 * 13p + 2 * 3

Perimeter = 26p + 6

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A rectangular lawn, 100 feet long by 50 feet wide, is to have two sidewalks installed that will cut the lawn in half both ways,
Damm [24]

Answer:

3.41 feet

Step-by-step explanation:

Area = Length × Breath

Area of the rectangular lawn = 100 × 50

                                                = 5000 feet²

The sidewalk must occupy an area no more than 10% of the total lawn area.

So, the area of the sidewalk would be not more than  = 10% × 5000

                                                                                         = 0.10 × 5000

                                                                                        = 500 feet²

Let the width of the sidewalk = x feet

area of the side walk = (L×W of the long way) + ((L-x)×W of the short way)

(100 × x) + ((50 - x) × x) < 500

100x + (50-x)(x) < 500

-x²  + 150x < 500

-x² + 150x = 500

-x² + 150x - 500 = 0

By using quadratic formula

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

x=\frac{(-150)\pm\sqrt{(150)^2-4(-1)(-500)} }{2(-1)}

x=\frac{-150\pm \sqrt{20500} }{-2}

x=75-5\sqrt{205} or x=75+5\sqrt{205}

x = 3.41089 ≈ 3.41 feet  or  x = 146.58

Therefore, width of the sidewalk would be 3.41 feet.

5 0
3 years ago
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Answer:

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= 4y^2 + 6y + 8y + 12

= 4y^2 + 14y + 12

Perimeter of a rectangle = 2 × (a +b)

= 2 × ( 4y + 6 + y+ 2)

= 2 × ( 5y + 8)

= 10y + 16

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