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andreyandreev [35.5K]
3 years ago
6

On a coordinate plane, triangle A B C has points (negative 3, negative 1), (negative 2, negative 3), (1, negative 1) and is refl

ected across y = 1. Reflect the figure over the line y = 1. Which is point A’ after the reflection? A’(–3, 1) A’(–3, 3) A’(–3, 2) A’(1, 1)
Mathematics
1 answer:
andreev551 [17]3 years ago
7 0

Answer:

A' = (-3, 3)

Step-by-step explanation:

If the points are as follows:

A = (-3, -1)

B = (-2, -3)

C = (1, -1)

When reflecting across a y axis the x values remain the same.

When reflecting across y = 1 the y values will remain equal distant from y = 1.

A' = (-3, 3) y value = |-1 - 1| = 2 + 1 = 3

B' = (-2, 5) y value = |-3 - 1| = 4 + 1 = 5

C' = (1, 3) y value = |-1 - 1| = 2 + 1 = 3

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Answer:

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Answer:

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".  

Solution to the problem

Let X the random variable who represents the variable of interest. We know from the problem that the distribution for the random variable X is given by:

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Why is the value of q?
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Given:

QSR is a right triangle.

QT = 10

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To find:

The value of q.

Solution:

Hypotenuse of QSR = QT + TR

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Do cross multiplication.

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Taking square root on both sides.

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