Any of #13-16 please?!

From a group of 13 women and 12 men, a researcher wants to randomly select 8 women and 8 men for a study. In how many ways can

Fantom [35]

The total number of ways the study can be selected is: 637065

Given,

Total number of women in a group= 13

Total number of men in a group = 12

Number of women chosen = 8

Number of men chosen = 8

∴ the total number of ways the study group can be selected = 13C₈ and 12C₈.

This in the form of combination factor = nCr

∴ nCr = n!/(n₋r)! r!

13C₈ = 13!/(13 ₋ 8)! 8!

= 13!/5!.8!

= 1287

12C₈ = 12!/(12₋8)! 8!

= 12!/5! 8!

= 495

Now multiply both the combinations of men and women

= 1287 × 495

= 637065

Hence the total number of ways the study group is selected is 637065

Learn more about "Permutations and Combinations" here-

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4 0

2 years ago

What’s the 5th term is 2,14,98

iragen [17]

$\bold{\huge{\orange{\underline{ Solution }}}}$

<h3>Correct Question :-</h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3>Given :- </h3>

We have AP, 

$\sf{ 2 , 14 ,.... 98 }$
AP is the arithmetic progression or a sequence of numbers in which succeeding number is differ from preceeding number by a common value.

<h3>Solution :-</h3>

We have an AP :- 2 , 14 .....98

Therefore,

$\sf{a1\: or \:1st\: term = 2 }$
$\sf{a2 \:or \:2nd\: term = 14 }$
$\sf{an \:or\: last\: term = 98}$

Here,

Common difference of an AP

$\sf{ a2 - a1 }$

$\sf{ = 14 - 2}$

$\sf{ = 12}$

Thus, The common difference is 12

Now, 

We know that,

$\sf{an = a1 + ( n - 1 )d}$

$\sf{a5 = 2 + ( 5 - 1 )12}$

$\sf{a5 = 2 + 4 × 12}$

$\sf{a5 = 2 + 48}$

$\sf{\red{a5 = 50}}$

Hence, The 5th term of given AP is 50

4 0

2 years ago

What is the following sum ?

Hitman42 [59]

Answer: 4th option

Explanation:

I added a picture so please check it

6 0

3 years ago

Read 2 more answers

If the graph of f(r)

kondor19780726 [428]

Answer:

yes yes yes yes no yes hcycrztdugguib

7 0

3 years ago

Many times business will raise the prices of their goods

hjlf

The price that will maximize profit is $ 5.50.

Since an auditorium has seats for 1200 people, and for the past several days, the auditorium has been filled to capacity for each show, and tickets currently cost $ 5.00 and the owner wants to increase the ticket prices, and he estimates that for each $ 0.50 increase in price, 100 fewer people will attend, to determine which is the price that will maximize profit, the following calculation must be made:

1200 x 5 = 6000
1100 x 5.5 = 6050
1000 x 6 = 6000

Therefore, the price that will maximize profit is $ 5.50.

Learn more in brainly.com/question/25313241

7 0

2 years ago