Using the slope - intercept relation, the required equation which models the scenario and Raul's speed are ;
- <em>y</em><em> </em><em>=</em><em> </em><em>-</em><em> </em><em>7.5x</em><em> </em><em>+</em><em> </em><em>15</em><em> </em>
- <em>4</em><em> </em><em>miles</em><em> </em><em>per</em><em> </em><em>hour</em><em> </em>
Time difference, Δt = 1.2 hours - 0.5 hours = 0.7 hours
Change in distance, Δd = 11.25 - 6 = 5.25 miles
Assuming a constant speed :
- Speed = (Δd ÷ Δt) = (5.25 ÷ 0.7) = 7.5 mi/hr
<u>Using the general form</u> :
At, x = 1.2 hours ;
Miles left, y = 6 miles
End point decreases by 7.5 mi/hr (-7.5 mi/hr)
Inputting the data into the equation :
6 = - 7.5(1.2) + c
6 = - 9 + c
c = 6 + 9 = 15 miles
<u>The expression in slope intercept form becomes</u> ;
<u>If Raul lives 5 miles closer to the beach</u> ;
<u>Time it will take Luis to get to the beach</u> :
- Time taken = (15 ÷ 7.5) = 2.5 hours
Distance Raul has to cover = 15 - 5 = 10 miles
To reach the beach after 2.5 hours ;
- Speed required = (10 ÷ 2.5) = 4 mi/hr
Therefore, Raul has to ride at 4 miles per hour for the plan to work.
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The same as the greatest number that can be written
with 10 binary bits: <u>1,024</u>
25 = 5^2
90 = 2 . 3 . 3 . 5
GCF is not as greedy as LCM.
GCF is just on a diet, so it takes the same number and the smallest amount.
25 and 90 both have 5.
5^2 or 5 ?
Take the smaller one.
GCF = 5
Answer:
Step-by-step explanation:
(a). B, C and D are the distinct points that are collinear.
(b). FC and BD are the distinct lines that intersect each other at a point C.
(c). E, F, C and A are the points that are coplanar (on the same plane).
(d). Another name for plane X is plane AEF. (Since a plane is defined by the three distinct points on the same plane.
