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2 years ago

PLS HELP I WILL GIVE BRAINLYEST 68% of what number is 137.9 m?

Mathematics

2 answers:

kherson [118]2 years ago

8 0

Answer:

968 is the answer for the question... Plz mark me as branlist answer

frutty [35]2 years ago

8 0

Answer:

238

Step-by-step explanation:

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differentiate the function and find the slope of the tangent line at the given value of the independent variable k(x)=1/2+x, x=2

aleksandrvk [35]

I didn't know which equation you were asking about, so I solved for both of them. I hope this helps!

Ignore the first guy who answered this question

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2 years ago

What is the volume of the prism shown below? O 8 cm O 10 cm O 12 cm3 O 16 cm3

Bogdan [553]

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3 years ago

Colt1911 [192]

Answer: 6x + 8y =1,245

Step-by-step explanation:

Hi, to answer this question we have to write an equation for each person:

Jack = The total cost (650) must be equal to the product of the number of shirts he bought (2) and the price per shirt (x); plus the product of the number of pair of jeans he bought (5) and the price per jean (y).

2 x+ 5 y=650

Dylan = The total cost (595) must be equal to the product of the number of shirts he bought (4) and the price per shirt (x); plus the product of the number of pair of jeans he bought (3) and the price per jean (y).

4x+3y = 595

Vertical addition:

2 x+ 5 y=650

4x+3y = 595

_________

6x + 8y =1,245

7 0

3 years ago

How do you solve this question? Any help appreciated!

fiasKO [112]

$\bf \displaystyle \int\limits_{1}^{e}\cfrac{1}{t}\cdot dt\\\\
-------------------------------\\\\
\textit{doing substitution}\\\\
u=\cfrac{1}{t}\implies u=t^{-1}\implies \cfrac{du}{dt}=-t^{-2}\implies \cfrac{du}{dt}=-\cfrac{1}{t^2}\\\\\\ -t^2du=dt\\\\
-------------------------------\\\\
\displaystyle \int\limits_{1}^{e}u\cdot -t^2du\impliedby \textit{now, let's do some substitution on the "t"}\\\\
-------------------------------\\\\$

$\bf u=\cfrac{1}{t}\implies t=\cfrac{1}{u}\implies t^2=\cfrac{1^2}{u^2}\implies t^2=\cfrac{1}{u^2}\\\\
-------------------------------\\\\
\displaystyle \int\limits_{1}^{e}u\cdot -\cfrac{1}{u^2}\cdot du\implies -1\int\limits_{1}^{e}\cfrac{1}{u}\cdot du\implies \left. -ln|u| \cfrac{}{}\right]_1^e$

$\bf \left. -ln\left( \frac{1}{t} \right) \cfrac{}{}\right]_1^e\implies 
\left[ -ln\left( \frac{1}{e} \right) \right]-\left[ -ln\left( \frac{1}{1} \right) \right]\implies 
\left[ -ln\left( e^{-1}\right) \right]-\left[ -ln\left( 1\right) \right]
\\\\\\\
[-(-1)]-[-(0)]\implies 1-0\implies 1$

8 0

3 years ago

What is the Slope= 7, (3,9)

lisov135 [29]

Where is the question? I have no idea what I need to do to help u?

5 0

3 years ago