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zhenek [66]
3 years ago
10

For your vegetable garden, you plan to plant 5 12 of it in corn, 1 6 in different kinds of beans, and 1 12 in tomatoes. You will

plant the remainder equally in eggplant, onions, and squash. What part of the garden will be planted in onions and squash combined
Mathematics
2 answers:
kati45 [8]3 years ago
8 0

Answer:

\frac{1}{9}

Step-by-step explanation:

Given:

Total fraction of garden for vegetation = \frac{5}{12}

Fraction of beans = \frac{1}{6}

Fraction of tomatoes = \frac{1}{12}

It will plant the remainder equally in eggplant, onions, and squash.

Question asked:

What part of the garden will be planted in onions and squash combined ?

Solution:

Total fraction of garden for vegetation =

Fraction of beans =

Fraction of tomatoes = \frac{1}{12}

Remaining fraction of garden = \frac{5}{12}-(\frac{1}{6} +\frac{1}{12} )

                                                 = \frac{5}{12} -\frac{1}{6} -\frac{1}{12}

Taking LCM of 12, 6 and 12    =\frac{5-2-1}{12} =\frac{2}{12} =\frac{1}{6}

Now, Remaining fraction for plant will be divided equally among eggplant, onions, and squash.

\frac{1}{6} \div3\\\frac{1}{6}\times\frac{1}{3} =\frac{1}{18}

Now, to find the combined fraction of onions and squash we will add both of the fraction.

Fraction of onions = \frac{1}{18}

Fraction of  squash = \frac{1}{18}

combined fraction of onions and squash = \frac{1}{18}+\frac{1}{18}

                                                                    = \frac{1+1}{18} =\frac{2}{18} = \frac{1}{9}

Therefore,  \frac{1}{9}  part of the garden will be planted in onions and squash combined.

Ymorist [56]3 years ago
6 0

Answer:

\frac{2}{9}  part of the garden will be planted in onions and squash combined.

Step-by-step explanation:

Given:

For your vegetable garden, you plan to plant 5 12 of it in corn, 1 6 in different kinds of beans, and 1 12 in tomatoes.

You will plant the remainder equally in eggplant, onions, and squash.

Now, to find the part of garden that will be planted in onions and squash combined.

Part of garden plan for planting corn = \frac{5}{12}

Part of garden plan for planting kinds of bean = \frac{1}{6}

Part of garden plan for planting tomatoes = \frac{1}{12}

So, adding all the parts of corn, beans and tomatoes:

\frac{5}{12}+\frac{1}{6}  +\frac{1}{12} \\\\=\frac{5+2+1}{12} \\\\=\frac{8}{12}

Now, to get the rest of the parts of garden use to plant eggplant, onions, and squash we subtract \frac{8}{12} from 1 whole:

1-\frac{8}{12} \\\\=\frac{12-8}{12} \\\\=\frac{4}{12}

As, given planting the remainder equally in eggplant, onions, and squash.

So, each will be planted in part of:

\frac{4}{12} \div 3

=\frac{4}{12}\times \frac{1}{3}

=\frac{4}{36}

On simplifying it:

=\frac{1}{9}.

Thus, \frac{1}{9}  part of the garden for each eggplant, onions, and squash.

Now, to get the part of the garden will be planted in onions and squash combined we add \frac{1}{9} part of garden planting for onions and \frac{1}{9} of squash:

\frac{1}{9} +\frac{1}{9} \\\\=\frac{1+1}{9} \\\\=\frac{2}{9}

Therefore, \frac{2}{9}  part of the garden will be planted in onions and squash combined.

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Answer:

4mfro• (2m2+10m+1)•(2m2+2m-3)

STEP

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Equation at the end of step 1

0-((((((((2•(m2))+10m)+1)•f)•r)•o)•m)•(((0-23m2)-8m)+12))

STEP

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Equation at the end of step

2

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0-(((((((2m2+10m)+1)•f)•r)•o)•m)•(-8m2-8m+12))

STEP

3

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Trying to factor by splitting the middle term

3.1 Factoring 2m2+10m+1

The first term is, 2m2 its coefficient is 2 .

The middle term is, +10m its coefficient is 10 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 2 • 1 = 2

Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is 10 .

-2 + -1 = -3

-1 + -2 = -3

1 + 2 = 3

2 + 1 = 3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

3

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0-((((f•(2m2+10m+1)•r)•o)•m)•(-8m2-8m+12))

STEP

4

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Equation at the end of step 4

0-(((fr•(2m2+10m+1)•o)•m)•(-8m2-8m+12))

STEP

5

:

Equation at the end of step 5

0-((fro•(2m2+10m+1)•m)•(-8m2-8m+12))

STEP

6

:

Equation at the end of step 6

0 - (mfro • (2m2 + 10m + 1) • (-8m2 - 8m + 12))

STEP

7

:

STEP

8

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Pulling out like terms

8.1 Pull out like factors :

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Trying to factor by splitting the middle term

8.2 Factoring 2m2 + 2m - 3

The first term is, 2m2 its coefficient is 2 .

The middle term is, +2m its coefficient is 2 .

The last term, "the constant", is -3

Step-1 : Multiply the coefficient of the first term by the constant 2 • -3 = -6

Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is 2 .

-6 + 1 = -5

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-2 + 3 = 1

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Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

8

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STEP

9

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Final result :

4mfro • (2m2 + 10m + 1) • (2m2 + 2m - 3)

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