Answer:
Step-by-step explanation:
<h3>A.</h3>
The equation for the model of the geyser is found by substituting the given upward velocity into the vertical motion model. The problem statement tells us v=69. We assume the height is measured from ground level, so c=0. Putting these values into the model gives ...
h(t) = -16t² +69t
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<h3>B.</h3>
The maximum height is at a time that is halfway between the zeros of the function.
h(t) = -16t(t -4.3125) . . . . . has zeros at t=0 and t=4.3125
The maximum height will occur at t=4.3125/2 = 2.15625 seconds. The height at that time is ...
h(t) = -16(2.15625)(2.15625 -4.3125) = 16(2.15625²) ≈ 74.39 . . . feet
The maximum height of the geyser is about 74.4 feet.
Length of 1 = 300 = 3 *10^2 nanometers
= 3*10^2/1*10^9 m
= 3*10^(2-9)
= 3*10^-7m
Step-by-step explanation:
f×0.2 = 182 ft²
20% is a factor 0.2, as it is 20 of 100.
Answer: 3.16, 8, 9, 12
Step-by-step explanation:
= 3.16
2^3 = 2 * 2 * 2 = 8
|-9| = 9
1.2 x 10^1 = 1.2 * 10 = 12
3.16, 8, 9, 12
Answer:
Zero, based on the information provided.
Step-by-step explanation:
The output rate of the teller machine is (1 transaction/6 minutes). The input rate is (1 customer/10 minutes). This means that the machine completes a cycle faster than the customers arrive, on the average. I don't know how an average can be calculated without more information. If we assume customers arrive every 10 minutes, and no one screws up the machine, that there should be no waiting line. Is there more information about when the customers arrive? E.g., 50 arrive in the first hour the machine is open.
