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3 years ago

8x(40+7)=(8x )+(8x7 what is the missing number

1 answer:

6 0

Well since the first expression says 8x(40+7) the answer would be 40 that is missing

Since your splitting 47 into 40 and 7 and multiplying both of them by 8 the answer would be 40

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What is the value of x in the equation x – y = 30, when y = 15?

erastovalidia [21]

x – y = 30, when y = 15

Then plug in the value

x - 15 = 30

Add 15 to both sides

x -15 + 15 = 30 + 15

Simplify:

x = 45

7 0

3 years ago

Read 2 more answers

Sphere A and Sphere B , are similar. The volumes of A and B, are 17 and 136 cubic centimetres, respectively. The diameter of B ,

xxMikexx [17]

Answer:

Step-by-step explanation:

Given: Sphere A and Sphere B are similar.

The volumes of A and B are 17 $cm^3$ and 136

The diameter of B is 6 cm.

To find: diameter of A

Solution:

Let R denotes radius of sphere A and r denotes radius of sphere B.

Radius of sphere A= R

Diameter of sphere B = 6 cm

So, radius of sphere B (r) = $\frac{6}{2}=3\,\,cm$

Volume of sphere is $\frac{4}{3}\pi(radius)^3$

Volume of sphere A = $\frac{4}{3}\pi(R)^3$

$\frac{\frac{4}{3}\pi R^3}{\frac{4}{3}\pi r^3}=\frac{17}{136}=\frac{1}{8}\\\frac{R^3}{r^3}=\frac{1}{8}\\\frac{R}{r}=\frac{1}{2}\\r=2R$

Put r = 3 cm

$3=2R\\R=\frac{3}{2}=1.5\,\,cm$

Diameter of sphere A = 2 × Diameter

= 2 × 1.5

=3 cm

6 0

3 years ago

If the average, mode, and range of 5 different numbers are all 8, find the sum of all possible values of the second largest numb

ANTONII [103]

I believe you meant:

If the average, mode, and range of 5 different numbers are all 8, find the sum of all possible values and the second largest number

Answer:

Sum of all possible values = 40

Second largest number= 8

Explanation:

Since our mean, mode, and range is 8, our sum is 40 and our second largest number is 8.

The sum of all the numbers is 40 since our mean is 8 and there are 5 numbers(8×5)

To find possible values, we already know the mode is 8 and so we know 8 must appear more than once. If we have 8 twice then we are left with 24(sum is 40). We have 3 numbers left and the range is 8 so we must have a maximum number and minimum number that has a difference of 8 and a third number, all adding up to 24(sum left). Within 24, only 12-4+8 satisfies the condition, hence our numbers are: 4,8,8,8,12.

3 0

3 years ago

The LCD of … A. 3 B. 3(x-5)^2 C. 3(x-5) D.x-5

victus00 [196]

Answer: $(c)$