What is an algebra teacher’s favorite breakfast

Write 0.0002839 in scientific notation.

Anika [276]

Answer:2.84 x 10-4

There you go!

8 0

3 years ago

Read 2 more answers

F(x)=2x-4. F(x)=2x-4 f-1x=_x+_. Complete the inverse function

natita [175]

Answer:

$f^{-1}(x) = \frac{1}{2}(x +4)$

Step-by-step explanation:

Given

$f(x) = 2x - 4$

Required

Determine the inverse function

Start by replacing f(x) with y

$y = 2x - 4$

Swap the positions of y and x

$x = 2y - 4$

Make y the subject: Add 4 to both sides

$x+4 = 2y - 4+4$

$x+4 = 2y$

Make y the subject: Divide through by 2

$\frac{1}{2}(x + 4) = y$

$y = \frac{1}{2}(x + 4)$

Replace y with f-1(x)

$f^{-1}(x) = \frac{1}{2}(x +4)$

3 0

2 years ago

PLZ HURRY!!!! 15 POINTS!

Daniel [21]

I think it’s 7.5 minutes

5 0

2 years ago

Read 2 more answers

Sophia earned $294 in 24 hours. How many dollars did she earn per hour?

Vadim26 [7]

Answer:

$12.25

Step-by-step explanation:

Step 1:

$294 : 24 Ratio

Step 2:

$294 ÷ 24 Divide

Answer:

$12.25

Hope This Helps :)

6 0

2 years ago

Read 2 more answers

Halla la tasa de variación de cada funcion en el intervalo [-4,3] e indica si es positiva , negativa o nula A) f(x)=x2-2x+4 B) f

masya89 [10]

Answer:

$A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative$

Step-by-step explanation:

Given a function $f(x)$ , we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value " $x_1$ " to another " $x_2$ ".

The rate of change of $f(x)$ between $x_1$ and $x_2$ can be calculated as follows:

$Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)$

For:

$f(x)=x^2-2x+4$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7$

So:

$Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative$

And for:

$f(x)-3x+2$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

So:

$Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative$

Translation:

Dada una función $f(x)$ , llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor " $x_1$ " a otro " $x_2$ ".

La tasa de variación de $f(x)$ entre $x_1$ y $x_2$ , puede ser calculada de la siguiente forma:

$Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)$

Para:

$f(x)=x^2-2x+4$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion =7-12=-5\hspace{3}Negativa$

Y para:

$f(x)-3x+2$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion=-7-14=-21\hspace{3}Negativa$

8 0

3 years ago