Answer:
The point of division is (5 , 8)
Step-by-step explanation:
* Lets explain how to solve the problem
- If point (x , y) divides the line whose endpoints are ![(x_{1},y_{1})](https://tex.z-dn.net/?f=%28x_%7B1%7D%2Cy_%7B1%7D%29)
and
at ratio
, then
and
![y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7By_%7B1%7Dm_%7B2%7D%2By_%7B2%7Dm_%7B1%7D%7D%7Bm_%7B1%7D%2Bm_%7B2%7D%7D)
* Lets solve the problem
- The directed line segment with endpoints A (3 , 2) and B (6 , 11)
- There is a point divides AB two-thirds from A to B
∵ The coordinates of the endpoints of the directed line segments
are A = (3 , 2) and B = (6 , 11)
∴
is (3 , 2)
∴
is (6 , 11)
∵ Point (x , y) divides AB two-thirds from A to B
- That means the distance from A to the point (x , y) is 2/3 from
the distance of the line AB, and the distance from the point (x , y)
to point B is 1/3 from the distance of the line AB
∴
= 2 : 1
∵ ![x=\frac{(3)(1)+(6)(2)}{2+1}=\frac{3+12}{3}=\frac{15}{3}=5](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B%283%29%281%29%2B%286%29%282%29%7D%7B2%2B1%7D%3D%5Cfrac%7B3%2B12%7D%7B3%7D%3D%5Cfrac%7B15%7D%7B3%7D%3D5)
∴ The x-coordinate of the point of division is 5
∵ ![y=\frac{(2)(1)+(11)(2)}{2+1}=\frac{2+22}{3}=\frac{24}{3}=8](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B%282%29%281%29%2B%2811%29%282%29%7D%7B2%2B1%7D%3D%5Cfrac%7B2%2B22%7D%7B3%7D%3D%5Cfrac%7B24%7D%7B3%7D%3D8)
∴ The y-coordinate of the point of division is 8
∴ The point of division is (5 , 8)