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dalvyx [7]
3 years ago
11

Does anyone know these?? please help :(

Mathematics
1 answer:
omeli [17]3 years ago
6 0
1- ABD
2- BC(with and arrow drawn above because it’s a ray) and BE (with and arrow drawn above because it’s a ray)
3- x=18
4- ABD=32
5- ABC=162
6- x=19
7- ABD=23
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Suppose x=9 tan (theta) and the angle (theta) is in the first quadrant. Write algebraic expressions for sin (theta) and cos (the
9966 [12]
The tangent trigonometric function is equal to the  quotient of sine and cosine through the trigonometric identity. In this case, we are given with x = 9 tan (theta). Hence the answer to this problem is the expounded algebraic expression x = 9 sin (theta) / cos (theta).
3 0
3 years ago
Need help with #6 <br> Find the missing angles
puteri [66]

Answer:

p = 95

q = 95

r = 85

s = 85

Step-by-step explanation:

85 deg & p are same-side int angles & are supplementary.

p = 180 - 85 = 95

p & q are vertical & congruent.

q = 95

p & s are supplenmentary.

s = 85

s & r are alt int angles & congruent.

r = 85

5 0
3 years ago
What is the equation of this graph? <br><br> Will get brainliest if answer is correct!
xz_007 [3.2K]

Answer:

I could be wrong but I think its the third one

Step-by-step explanation:

7 0
3 years ago
Suppose that, in addition to edge capacities, a flow network has vertex capacities. That is each vertex has a limit l./ on how m
storchak [24]

Answer:

See explanation and answer below.

Step-by-step explanation:

The tranformation

For this case we need to construct G' dividing making a division for each vertex v of G into 3 edges that on this case are v_1, v_2 and l(v).

We assume that the edges from the begin are the incoming edges of v_1 and all the outgoing edges from v are outgoing edges from v_2

We need to construct G' = (V', E') with capacity function a' and we need to satisfy the follwoing:

For every v \in V we create 2 vertices v_1, v_2 \in V'

Now we can add a new edge asscoiated to v_1, v_2 \in E' with the condition a' (v_1,v_2) = l(v)

Now for each edges (u,v)\in E we can create the following edge ( u_r, v_1) \in E' and the capacity is given by: a' (u_r, v_1) = a (u,v)

And for this case we can see this:

|V'| = 2|V|, |E'|= |E| +|V|

Now we assume that x is the flow who belongs to G respect vertex capabilities. We can create a flow function x' who belongs to G' with the following steps:

For every edge (u,v) \in G we can assume that x' (u_r ,v_1) = x(u,v)

Then for each vertex u \in V -t and we can define x\(u_1,u_r) = \sum_{v \in V} x(u,v) and x' (t_1,t_2) = \sum_{v \in V} x(v,t)

And after see that the capacity constraint on this case would be satisfied since for every edge in G' on the form (u_r, u_1) we have a corresponding edge in G because:

u \in V -(s,t) we have that:

x' (u_1, u_r) = \sum_{v \in V} x(u,v) \leq l(u) = a' (u_1, u_r)

x' (t_1,t_2) = \sum_{v \in V} x(v,t) \leq (t) = a' (t_1,t_2)

And with this we have the maximization problem solved.  

We assume that we have K vertices using the max scale algorithm.

6 0
3 years ago
The mother gave the two sons the same amount of money. When the older son spent $ 275 and the younger $ 250, the younger had 3 t
defon

Answer:

<em>Each son received from their mother $287.50</em>

Step-by-step explanation:

3(x - 275) = x - 250

2x = 825 - 250

<em>x = 287.50 </em>

$287.50 - $275 = $12.50

<u><em>Check the answer:</em></u>

After spending the older son has $12.50  

$287.50 - $250 = $37.50

After spending the younger son has $37.50

$37.50 ÷ $12.50 = 3 times

7 0
3 years ago
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